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klio [65]
3 years ago
9

You and your friend live in different states and plant identical hydrangea bulbs in your garden. When they bloom, you send each

other pictures. You notice that even though you bought the exact same kind of plant, your hydrangea flowers are blue and your friend’s are pink! On a hunch, you each measure the pH of your soil and find that your soil is a little acidic and your friend’s is a little basic. Why do you think the flowers have different colors?
Physics
2 answers:
Whitepunk [10]3 years ago
8 0

Answer:

sample. rewrite in your own words if you'd like.

Explanation:

Since the hydrangeas are changing color depending on whether the soil is acidic or basic, they must have an indicator. This means that any hydrangea planted in acidic soil will have blue flowers and any hydrangea planted in basic soil will have pink. One common indicator present in many plants is anthocyanin, so maybe hydrangeas contain that chemical.

Gwar [14]3 years ago
8 0

Answer:

it might be late but for those he need it and chenge the words

Explanation:

The hydrangeas are behaving like indicators.  The hydrangeas will be blue in any acidic soil and pink in any basic soil.  Hydrangeas must contain an indicating chemical such as anthocyanin.

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Answer:

0.331m

Explanation:

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v=30000m/s

f=90500 Hz

λ= \frac{v}{f}

λ= \frac{30000}{90500}

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5 0
2 years ago
Which of the following is most useful to determine how much energy is being used by a circuit in a given amount of time?
user100 [1]

Answer:

The answer is A.

Explanation:

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3 years ago
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Nataly_w [17]

Answer:

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Explanation:

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2 years ago
A parallel-plate capacitor has a plate area of 0.2m^2 and a plate separation of 0.1mm. To obtain an electric field of 2.0 × 10^6
Oduvanchick [21]

Answer:

3.536*10^-6 C

Explanation:

The magnitude of the charge is expresses as Q = CV

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V is the voltage across the capacitor

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C = ε0A/d

ε0 is the permittivity of the dielectric = 8.84 x 10-12 F/m

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Substitute

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C = 1.768 x 10-8 F

Get the potential difference V

Using the formula for Electric field intensity

E = V/d

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V = 2.0 × 10^6  * 0.0001

V = 2.0 × 10^2V

Get the charge on each plate.

Q = CV

Q =  1.768 x 10-8 * 2.0 × 10^2

Q = 3.536*10^-6 C

Hence the magnitude of the charge on each plate should be 3.536*10^-6 C

5 0
3 years ago
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vredina [299]
Fist one is a cylinder
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2 years ago
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