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nadezda [96]
3 years ago
10

What is an example of situational irony in the excerpt?​

Physics
2 answers:
Tomtit [17]3 years ago
7 0

Answer:

  • <u>Situational irony:</u>

"The situation of irony in which the actions done by a person brings  unexpected and more over brings the opposite results to the person."

Explanation:

<u>Example</u>:

If a kid has the daily routine to wake up in the morning and dress up to go to school.And one day he wakes up and wears his school uniform, after which he finds out that today is off or its Sunday. So, that situation is characterized as situational irony in general.

Murrr4er [49]3 years ago
6 0
Which excerpt are you talking about?
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Assuming all object are moving with the same velocity, witch statement describes the object with the largest intertia?
Kisachek [45]

Answer:

Mass is the quantitative measure of inertia of any object.

Explanation:

The object that have largest mass will   have largest inertia as well as largest momentum.

3 0
3 years ago
Can someone please help me
Mars2501 [29]
The correct answer is letter b.

To find the answer follow the following steps.
1. 6524.96 x .25 = X

2. 1631.24 = X

This works for all of the given answers to find the correct answer.
5 0
3 years ago
A transformer has a primary voltage of 115 V and a secondary voltage of 24 V. If the number of turns in the primary is 345, how
Eduardwww [97]
Here's a fun and useful factoid:

               The ratio of the voltages on a transformer is the same
               as the ratio of the number of turns in each winding.

So the ratio of  (345 to the secondary turns)  is  (115V to 24V).

That's a proportion.

                 (115/24)  =  (345/x)

I'll bet you can take it and solve it from here.
Just cross-multiply in the proportion and etc. etc.
6 0
3 years ago
Help again i need it quick
Romashka [77]

Answer:

it seems that the answer should be 7.5 mph as the average

Explanation:

sorry i did (s x t) when it was (s/t)

3 0
2 years ago
Read 2 more answers
A train of mass 3.3 × 10^6 kg is moving at a constant speed up a slope inclined at an angle of 0.64°
AnnyKZ [126]

Answer:

C. 39 m/s

Explanation:

First we need to calculate the total force required to move the train along the inclined plane. So, it is clear that the work done will be equal to the component of the weight that is parallel to the inclined plane, because there is no frictional force present:

Force = F = mg Sin θ

where,

m = mass of train = 3.3 x 10⁶ kg

g = 9.8 m/s²

θ = Angle of Inclination = 0.64°

Therefore,

F = (3.3 x 10⁶ kg)(9.8 m/s²)Sin 0.64°

F = 3.612 x 10⁵ N

Now, the formula for power is:

P = FV

V = P/F

where,

V = Velocity of Train = ?

P = Power of Engine = 14 MW = 1.4 x 10⁷ W

Therefore,

V = 1.4 x 10⁷ W/3.612 x 10⁵ N

V = 38.75 m/s

which is approximately equal to:

<u>C. 39 m/s</u>

4 0
3 years ago
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