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Dahasolnce [82]

3 years ago

15

Ethan made a diagram to compare examples of the first and second laws of thermodynamics. What belongs in the areas marked X and

Y?

2 answers:

Thepotemich [5.8K]3 years ago

3 0

<u>First law of thermodynamics:</u>

It states that <em>"Energy neither be created nor it can be destroyed". </em>simply it converts one form of energy into another form.

It is also known as<em> "law of conservation of energy"</em>

<u>Limitations of First law</u>

It doesn't provide a clear idea about the direction of transfer of heat.
It doesn't provide the information that how much heat energy converted inti work.
Its not given any practical applications.

<u>II law of thermodynamics:</u>

It states that <em>"the total entropy of the system can never decrease over time"</em>

It is strongly proved by two laws, they are

<em>1. Kelvin-plank statement:</em>

He stated that "any engine does not give 100% efficiency". It violates the Perpetual motion of machine II kind<em>(PMM-II).</em>

<em>2. Classius statement: </em>

<em> </em><em> It states that "Heat always flows from high temperature body to low temperature body, without aid of external energy". </em>

<em> Also it stated that " Heat can also be transferred from low temperature body to high temperature body, by the aid of an external energy".</em>

<em>Applications of II law: </em>

<em>Refrigeration &Air conditioning, Heat transfer, I.C. engines, etc.</em>

KatRina [158]3 years ago

3 0

Answer:

The answer is D.

Explanation:

I just took the quiz.

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A drag racing car with a weight of 1600 lbf attains a speed of 270 mph in a quarter-mile race. Immediately after passing the tim

Kaylis [27]

Answer:

15.065ft

Explanation:

To solve this problem it is necessary to consider the aerodynamic concepts related to the Drag Force.

By definition the drag force is expressed as:

$F_D = -\frac{1}{2}\rho V^2 C_d A$

Where

$\rho$ is the density of the flow

V = Velocity

$C_d$ = Drag coefficient

A = Area

For a Car is defined the drag coefficient as 0.3, while the density of air in normal conditions is 1.21kg/m^3

For second Newton's Law the Force is also defined as,

$F=ma=m\frac{dV}{dt}$

Equating both equations we have:

$m\frac{dV}{dt}=-\frac{1}{2}\rho V^2 C_d A$

$m(dV)=-\frac{1}{2}\rho C_d A (dt)$

$\frac{1}{V^2 }(dV)=-\frac{1}{2m}\rho C_d A (dt)$

Integrating

$\int \frac{1}{V^2 }(dV)= - \int\frac{1}{2m}\rho C_d A (dt)$

$-\frac{1}{V}\big|^{V_f}_{V_i}=\frac{1}{2m}(\rho)C_d (\pi r^2) \Delta t$

Here,

$V_f = 60mph = 26.82m/s$

$V_i = 120.7m/s$

$m= 1600lbf = 725.747Kg$

$\rho = 1.21 kg/m^3$

$C_d = 0.3$

$\Delta t=7s$

Replacing:

$\frac{-1}{26.82}+\frac{1}{120.7} = \frac{1}{2(725.747)}(1.21)(0.3)(\pi r^2) (7)$

$-0.029 = -5.4997r^2$

$r = 2.2963m$

$d= r*2 = 4.592m \approx 15.065ft$

4 0

4 years ago

Can someone help me with universal gravation

Nesterboy [21]

States that particles are attracts with every other particle. wich force is directily proportional product of two masses and inversely proportional to the distance between the centers.

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3 years ago

A theory is a hyothesis that has been varified by multiple investigations. <br> True or false

irakobra [83]

<span>A theory is a hyothesis that has been varified by multiple investigations.

true</span>

7 0

3 years ago

Weak magnetic fields can be measured at the surface of the brain. Although the currents causing these fields are quite complicat

STALIN [3.7K]

To develop this problem it is necessary to apply the concepts related to a magnetic field in spheres.

By definition we know that the magnetic field in a sphere can be described as

$B = \frac{\mu_0}{2}\frac{Ia^2}{(z^2+a^2)^{3/2}}$

Where,

a = Radius

z = Distance to the magnetic field

I = Current

$\mu_0 =$ Permeability constant in free space

Our values are given as

$D=2a = 16cm \rightarrow$ diameter of the sphere then,

$a = 0.08m$

Thus z = a

$B = \frac{\mu_0}{2}\frac{Ia^2}{(a^2+a^2)^{3/2}}$

$B = \frac{\mu_0I}{2(2^{3/2})a}$

$B = \frac{\mu_0 I}{2^{5/2}a}$

Re-arrange to find I,

$I = \frac{2^{5/2}Ba}{\mu_0}$

$I = \frac{2^{5/2}(3*10^{-12})(8*10^{-2})}{4\pi*10^{-7}}$

$I = 1.08*10^{-6}A$

Therefore the current at the pole of this sphere is $1.08*10^{-6}A$

5 0

3 years ago

a 250g moves eastward along a straight path at a constant velocity of 12 m per second calculate the momentum of the ball

lara31 [8.8K]

Explanation:

If two particles are involved in an elastic collision, the velocity of the second particle after collision can be expressed as: v2f=2⋅m1(m2+m1)v1i+(m2−m1)(m2+m1)v2i v 2 f = 2 ⋅ m 1 ( m 2 + m 1 ) v 1 i + ( m 2 − m 1 ) ( m 2 + m 1 ) v 2 i .

6 0

3 years ago