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sergij07 [2.7K]
2 years ago
5

(1/7x + 3/8) + (2/9x - 1/8)

Mathematics
1 answer:
Brrunno [24]2 years ago
3 0
(1/7x +2/9x) +(3/8-1/8)= 23/63x+1/4
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A banner is in the shape of a rectangle.It is 18 feet long and 9 feet wide.What is its perimeter?
Hatshy [7]

The given problem can be exemplified in the following diagram:

The perimeter of a figure is the sum of all of its sides, therefore, the perimeter of the figure is:

P=18ft+18ft+9ft+9ft

Adding the terms:

P=54ft

therefore, the perimeter is 54 feet.

6 0
1 year ago
1) reflect the point (7,9) across the x-axis
anzhelika [568]
1) (7,-9)
2) (-7,9)

Hope this helps! :)
4 0
3 years ago
In the figure below, the following is true: angle ABD is congruent to angle CDB and angle DBC is congruent to angle BDA. How can
sergiy2304 [10]
<span>triangle ABD and the triangle CDB are similar 
the options are </span><span>ASA and CPCTC</span>
7 0
3 years ago
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Find X: <br> tangent, cosine or sine?
Gnom [1K]

Answer:

x ≈ 2.76

Step-by-step explanation:

Using the tangent ratio in the right triangle

tan78° = \frac{opposite}{adjacent} = \frac{AB}{BC} = \frac{13}{x} ( multiply both sides by x )

x × tan78° = 13 ( divide both sides by tan78° )

x = \frac{13}{tan78} ≈ 2.76 ( to 2 dec. places )

4 0
2 years ago
4.. Please help. Is DE←→ perpendicular to FG←→? Why or why not?
olya-2409 [2.1K]

Given:

DE contains the points D(1, -2) and E(3, 4).

FG contains the points F(-1, 2) and G(4, 0).

To find:

Is DE perpendicular to FG.

Solution:

Slope of DE:

$m=\frac{y_2-y_1}{x_2-x_1}

Here x_1=1, y_1=-2, x_2=3, y_2=4

$m=\frac{4-(-2)}{3-1}

$m=\frac{6}{2}

m = 3

Slope of FG:

$m=\frac{y_2-y_1}{x_2-x_1}

Here x_1=-1, y_1=2, x_2=4, y_2=0

$m=\frac{0-2}{4-(-1)}

$m=\frac{-2}{4+1}

$m=\frac{-2}{5}

<em>Two lines are perpendicular if product their slopes are -1.</em>

Slope of DE × Slope of FG

         $=3\times \frac{-2}{5}

         $= \frac{-6}{5}

         ≠ -1

The solution is no, because the product of the slopes is not -1.

3 0
3 years ago
Read 2 more answers
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