A sign board supported by two strings does illustrate the tension-tension and weight in the free body diagram.
In a sign board supported by two strings, there will be tension in each strings and a force of weight downward due to the mass of the body. The tension of both strings will be in equilibrium to weight of the object.
There will be elastic force or spring force also we can say if a rubber band is being stretched by a person.
A torque will be applied on the door when pulled by two applied forces but there will be no tension.
If a book fall from a table then the book will go under free fall motion, hence there is no possibility of tension tension on the book.
Hence we can conclude that tension tension and weight force will only be there, where we will be having an object supported by strings, also go through the diagram attached for better understanding.
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Answer:
0
Explanation:
When y=0, the line is on the x axis, which means that it is at a speed on 0.
Answer:
Frequency, f = 0.2 Hz
Explanation:
We have,
A baseball player throws 4 balls every 20 seconds.
It is required to find the frequency of the baseball.
Frequency of an object is defined as the number of times an event occurs. It is given by number of throws per unit time. It can be given by :
![f=\dfrac{4}{20}\\\\f=0.2\ Hz](https://tex.z-dn.net/?f=f%3D%5Cdfrac%7B4%7D%7B20%7D%5C%5C%5C%5Cf%3D0.2%5C%20Hz)
So, the frequency of his throw is 0.2 Hz.
This question is checking to see whether you understand the meaning
of "displacement".
Displacement is a vector:
-- Its magnitude (size) is the distance between the start-point and
the end-point, no matter what route might have been followed along
the way.
-- Its direction is the direction from the start-point to the end-point.
Talking about the Earth's orbit around the sun, we can forget about
the direction of the displacement, and just talk about its magnitude
(size).
If we pretend that the sun is not moving and dragging the whole
solar system along with it, then what do we see the Earth doing
in one year ?
We mark the place where the Earth is at the stroke of midnight
on New Year's Eve. Then we watch it as it swings around through
this gigantic orbit, all the way around the sun, and in a year, it's back
to the same point that we marked !
So what's the magnitude of the displacement in exactly one year ?
It's the distance between the start-point and the end-point. But the
Earth came back to the same place it started from, so there's no
separation at all between the start-point and the end-point.
The Earth covered a huge distance in that year, but the displacement
is zero.
The least value varies depends on ammeter range. In the given question, ammeter range is not mentioned. So, the least value of an ammeter is 0.1 or 0.5 (depends on ammeter range).
<u>Explanation:</u>
The least value of an ammeter is the measure of the smallest number which can be observed in ammeter. So the least value will be varying depending upon its range. If we consider the range of ammeter is 30 A and the scale readings are 10 numbers, then the least value will be 30/10 = 3 A per scale.
So the least value is determined as ![\frac{Range of ammeter}{No.of scales}](https://tex.z-dn.net/?f=%5Cfrac%7BRange%20of%20ammeter%7D%7BNo.of%20scales%7D)
So among the given options 0.1 is most suitable for an ammeter with range of 3 A with 30 divisions.