The glass around the bulb in a clinical thermometer (the conventional one) is <span>thin because glass is not a good conductor of heat. The clinician and the
</span>patient don't want to wait half an hour to get a good temperature reading. By <span>using the thinner glass, the transfer of heat into the thermometer's fluid will</span>
Answer:
2.0*
Explanation:
Let us calculate total moles (air + CO)
moles (n) = PV /RT
P = 755 torr/760 = 0.9934 atm
V = 1.00 L
R = gas constant
T = 23°C + 273 = 296 K
So,
total moles (n) = 0.9934 x 1.00/0.0821 x 296 = 0.041 moles
mole fraction of CO = 8.1 x
moles of CO =8.1 x *0.041
=3.31 x moles
number of molecule of CO =3.31 x *(6.0233x )
= 2.0*
Answer:
the planet which is like earth and have suitable environment for living is called exoplanet
Answer:
Explanation:
mass of string = .0125 / 9.8
= 1.275 x 10⁻³ kg
Length of string l = 1.5 m .
m = mass per unit length
= ( .1.275 / 1.5) x 10⁻³ kg/m
m = .85 x 10⁻³ kg/m
wave equation: y(x,t) = (8.50 mm)cos(172 rad/m x − 4830 rad/s t)
compare with equation of wave
y(x,t) = Acos(K x − ω t)
ω ( angular velocity ) = 4830 rad/s
k = 172 rad/m
Velocity = ω / k
= 4830/172 m /s
= 28.08 m /s
velocity of wave =
28.08 =
788.48 = W / .85 X 10⁻³
W = 670 x 10⁻³ N .
c ) wave length
wave length =2π / k
= 2 x 3.14 / 172
= .0365 m
no of wave lengths over whole length of string
= 1.5 / .0365
= 41
d )
equation for waves traveling down the string
= (8.50 mm)cos(172 rad/m x + 4830 rad/s t)
Answer:
1.53 cm
Explanation:
The relationship between wavelength and frequency for a wave is:
where
v is the speed of the wave
f is the frequency
is the wavelength
In this problem, we have:
is the frequency of the ultrasound wave
is the speed of sound in sea water at room temperature
Re-arranging the previous equation and solving for , we find the wavelength of the ultrasound wave: