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antoniya [11.8K]
2 years ago
13

Explain why sliding friction is less than stactic friction

Physics
1 answer:
Alik [6]2 years ago
7 0

Answer:

here it is...

Explanation:

The friction between the two surfaces is because of the interlocking of the irregularities of the two surfaces. During sliding, contact points do not get enough time to get interlocked properly. Therefore, less friction. ... This explains why sliding friction is less than static friction.

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3 years ago
If the resistance of a circuit increases, that means that the current has to
Gnoma [55]

Answer:

If resistance increases current decreases.

Explanation:

  • Current is <em>inversely proportional</em> to the resistance.
  • from the relation given below, we can clearly see the relation between current and resistance;

                              V=IR

                              I ∝ 1/R

This relation shows that when resistance increases,current decreases.

4 0
3 years ago
How did you know if an electric current is<br> flowing in a lightbulb?
sweet [91]

Answer:

if it lights up

Explanation:

electricity

7 0
3 years ago
A soccer ball is kicked At 8m/s. It lands on the ground after being in the air for .85 seconds. At what angle is it kicked?
SpyIntel [72]

If ball remains in air for total time T = 0.85 s

this is also known as time of flight

In order to find the time of flight we can use kinematics

\Delta Y = v_y*t + \frac{1}{2}at^2

so for complete motion its displacement in y direction will be zero

0 = v_y* 0.85 + \frac{1}{2}(-9.8)(0.85^2)

0 = v_y*0.85 - 3.54

v_y = 4.165 m/s

now we know that net velocity of the ball is 8 m/s

while is y direction component we got is vy = 4.165 m/s

now by component method we can say

v_y = v sin\theta

4.165 = 8 sin\theta

\theta = sin^{-1}\frac{4.165}{8}

\theta = 31.4^0

so it is projected at an angle of 31.4 degree above horizontal

8 0
3 years ago
n the figure, a uniform ladder 12 meters long rests against a vertical frictionless wall. The ladder weighs 400 N and makes an a
Leto [7]

Since the ladder is standing, we know that the coefficient of friction is at least something. This [gotta be at least this] friction coefficient can be calculated. As the man begins to climb the ladder, the friction can even be less than the free-standing friction coefficient. However, as the man climbs the ladder, more and more friction is required. Since he eventually slips, we know that friction is less than what's required at the top of the ladder.

 

The only "answer" to this problem is putting lower and upper bounds on the coefficient. For the lower one, find how much friction the ladder needs to stand by itself. For the most that friction could be, find what friction is when the man reaches the top of the ladder.

Ff = uN1

Fx = 0 = Ff + N2

Fy = 0 = N1 – 400 – 864

N1 = 1264 N

Torque balance

T = 0 = N2(12)sin(60) – 400(6)cos(60) – 864(7.8)cos(60)

N2 = 439 N

Ff = 439= u N1

U = 440 / 1264 = 0.3481

3 0
3 years ago
Read 2 more answers
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