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3 years ago

0/1 What is the equation of the line in y=mx+b form? (Photo)

Mathematics

1 answer:

laiz [17]3 years ago

6 0

Answer:

y=-15x+100

Step-by-step explanation:

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An airport limousine can accommodate up to four passengers on any one trip. The company will accept a maximum of six reservation

tensa zangetsu [6.8K]

Answer:

i think c

Step-by-step explanation:

3 0

3 years ago

Please can someone help me, thank u

Goshia [24]

Answer:

Step-by-step explanation:

4×22/7×2.6^2=85.0cm

5 0

3 years ago

Simplify 6x/10x2\6/10x3-60x2<br> A.x-6<br> B.x-4<br> C.4<br> D.x-1

Anna71 [15]

Answer:

A. x-6

Step-by-step explanation:

Maybe you want to simplify ...

((6x)/(10x^2))/(6/(10x^3 -60x^2))

Invert and multiply. Cancel common factors from numerator and denominator.

$\dfrac{\left(\dfrac{6x}{10x^2}\right)}{\left(\dfrac{6}{10x^3-60x^2}\right)}=\dfrac{6x}{10x^2}\cdot\dfrac{10x^3-60x^2}{6}=\dfrac{6\cdot10x^2}{6\cdot10x^2}(x-6)\\\\=\boxed{x-6}$

3 0

4 years ago

What is a point-Slope equation of the line with slope -10 that goes thought the point (1,4)?

professor190 [17]

The point slope equation would be one of the equations with -10 in front because it multiplies into x as the negative 10 slope. That narrows it down to C and D. Then the points show 1 and 4 and it has to be positive. That narrows it down the answer D. If this is right could you possibly give me brainliest? Hope this helped.

6 0

3 years ago

You have two circles, one with radius r and the other with radius R. You wish for the difference in the areas of these two circl

gtnhenbr [62]

Answer:

maximum difference of radii = $(r-R)=\frac{1}{2\pi ^{2}}$

Step-by-step explanation:

We know that area of circle is given by

$A=\pi \times (radius)^{2}$

For circle with radius 'r' we have

$A_{1}=\pi \times (r)^{2}$

For circle with radius 'R' we have

$A_{2}=\pi \times (R)^{2}$

Now according to given condition we have

$A_{1}-A_{2}\leq \frac{5}{\pi }$

$\Rightarrow \pi r^{2}-\pi R^{2}\leq \frac{5}{\pi }\\\\\Rightarrow (r^{2}-R^{2})\leq \frac{5}{\pi ^{2}}\\\\(r+R)(r-R)\leq \frac{5}{\pi ^{2}}\\\\\because (a^{2}-b^{2})=(a+b)(a-b)\\\\(r+R)=10(Given)\\\\\Rightarrow(r-R)\leq \frac{5}{10\pi ^{2}}\\\\\therefore (r-R)\leq\frac{1}{2\pi ^{2}}$

Thus maximum difference of radii = $(r-R)=\frac{1}{2\pi ^{2}}$

6 0

4 years ago