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Veronika [31]
2 years ago
13

Problems that I am stuck on! Need the answers asap

Chemistry
1 answer:
Anna71 [15]2 years ago
6 0

Answer:

1.b

2.b

3.a

4.a

Explanation:

use the rate laws when answering this.

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What could J.J. Thomson conclude from his experiments?
KonstantinChe [14]

Answer:C, atoms must balance positive and negative particles.

Explanation: Got it correct on edgenuity.

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3 years ago
1. Experimental Design: From the work you have done this semester, choose a topic and design an experiment you would be able to
Papessa [141]

Take two plants - ensure that both get the same amount of sunlight, but one will get little water and the other more water. Water would be the manipulated variable; the sun would be the independent variable and there is only one control. (1) make an observation; “water makes plants grow.” (2) draft the hypothesis “...if____ the ____.” (3) conduct the experiment; (4) gather the data; (5) Do the analysis to support or deny your hypothesis; and (6) repeat if necessary.

7 0
3 years ago
PLEASE ANSWER!!!!<br><br><br> what is mass and volume????
azamat
Mass and volume are two units used to measure objects. Mass- the amount of matter an object contains and volume- how much space it takes up
6 0
3 years ago
Read 2 more answers
How many moles are in 0.821g of lead?
Ivenika [448]

Answer:

3.96 × 10⁻³ mol Pb

Explanation:

Step 1: Find molar mass

Pb (Lead) - 207.2 g/mol

Step 2: Use Dimensional Analysis

0.821 \hspace{2} g \hspace{2} Pb(\frac{1 \hspace{2} mol \hspace{2} Pb}{207.2 \hspace{2} g \hspace{2} Pb} ) = 0.003962 mol Pb

Step 3: Simplify

We have 3 sig figs

0.003962 mol Pb ≈ 0.00396 mol Pb

0.00396 mol Pb = 3.96 × 10⁻³ mol Pb

3 0
3 years ago
What is the molality of a solution made by combining 5.0 g of CaCl2 with 500.0 g of water?
ankoles [38]
Molality is defined as the number of moles of solute dissolved in 1 kg of solvent.
To calculate molality, we need to calculate the number of moles of CaCl₂.
Mass of CaCl₂ - 5.0 g
Molar mass of CaCl₂ - 111 g/mol
The number of moles of CaCl₂ - 5.0 g / 111 g/mol = 0.045 mol 
we need to then calculate the number of moles in 1 kg solvent.
number of CaCl₂ moles in 500 g water - 0.045 mol
Therefore number of moles in 1 kg water - 0.045 mol / 500g x 1000 g = 0.090 mol
Molality of CaCl₂ - 0.090 mol/kg

5 0
4 years ago
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