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Veronika [31]
2 years ago
13

Problems that I am stuck on! Need the answers asap

Chemistry
1 answer:
Anna71 [15]2 years ago
6 0

Answer:

1.b

2.b

3.a

4.a

Explanation:

use the rate laws when answering this.

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What is the Arrhenius definition of an acid
matrenka [14]

The answer to your question is,

An Arrhenius acid is a type of substance that separates in water to form Hydrogen ions.

-Mabel <3

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3 years ago
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Pubhvcghbb<br> Jgyukbcu?
tino4ka555 [31]

Answer:

WHAT??

Explanation:

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3 years ago
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Has anyone ever done this atom escape room thing
SVEN [57.7K]

Answer:

1.  negative

2.  positive

3.  neutral

Explanation:

Ok so it looks like they are asking for the charge (positive, negative, or neutral) of each thing

So for 1, it would be negative, because it's pointing to an electron.  Electrons always have a negative charge.

So for 2, it would be positive, because it's pointing to a proton.  Protons always have a positive charge

So for 3, it would be neutral, because it's pointing to a neutron.  Neutrons always have a neutral charge.

4 0
3 years ago
Question 1 (4 points)
oee [108]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

Blank # 1 - keep safe distance from the burner

Blank # 2 - Place the equipments on the right place after use

Blank # 3 - perform experiments with proper lab equipment and safety tools

Blank # 4 - Don't break any test tube or lab equipment

(maybe it can be hazardous)

4 0
3 years ago
How many milliliters of a 1.5 m h2so4 are needed to neutralize 35ml sample of a 1.5 m solution?
DochEvi [55]

Answer:

1) 17.5 mL

Explanation:

Hello,

In this case, the reaction between sulfuric acid and potassium hydroxide is:

H_2SO_4+2KOH\rightarrow K_2SO_4+2H_2O

In such a way, we notice a 1:2 molar ratio between the acid and the base, therefore, at the equivalence point we have:

2*n_{acid}=n_{base}

And in terms of concentrations and volumes:

2*M_{acid}V_{acid}=M_{base}V_{base}

Thus, we solve for the volume of acid:

V_{acid}=\frac{M_{base}V_{base}}{2*M_{acid}} =\frac{35mL*1.5M}{2*1.5M} \\\\V_{acid}=17.5mL

Best regards.

5 0
3 years ago
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