Answer:
142.82 g
Explanation:
The following data were obtained from the question:
Volume of water = 12 mL
Volume of water + gold = 19.4 mL
Density of gol= 19.3 g/cm³
Mass of gold =.?
Next, we shall determine the volume of the gold. This can be obtained as follow:
Volume of water = 12 mL
Volume of water + gold = 19.4 mL
Volume of gold =.?
Volume of gold = (Volume of water + gold) – (Volume of water)
Volume of gold = 19.4 – 12
Volume of gold = 7.4 mL
Finally, we shall determine the mass of the gold as follow:
Note: 1 mL is equivalent to 1 cm³
Volume of gold = 7.4 mL
Density of gol= 19.3 g/cm³ = 19.3 g/mL
Mass of gold =?
Density = mass /volume
19.3 = mass of gold /7.4
Cross multiply
Mass of gold = 19.3 × 7.4
Mass of gold = 142.82 g
Therefore, the mass of the gold pebble is 142.82 g
Answer:
My chemistry teacher from my sophomore year.
Explanation:
I took class online last year and he was an older teacher and really didn't know how to use a computer. I asked for help multiple times and he would tell me to look the answer up. I would watch countless videos and still wouldn't understand. He ended up failing me that year and I had summer school. To this day, I dislike chemistry because of him.
Mixture; it contains water, surgar, fat, protein, etc.
Answer:
1.63 kilo Joules of energy will be produced when 14.8 g of silver nitrate react.
Explanation:
Mass of silver nitrate = 14.8 g
Moles of silver nitrate = 
According to reaction, when 1 mole of silver nitrate reacts with 1 mole of calcium it gives 18.7 kJ of heat.
Then amount of heat released when 0.08706 moles of silver nitrate reacts :
1.63 kilo Joules of energy will be produced when 14.8 g of silver nitrate react.
Answer: Value of impulse is 
Explanation: lmpulse is defined as the amount of force acting over a short time interval 't' which is equal to the change in momentum of the body having mass 'm'.
Mathematically,
And,
Given:
Putting values in above equation, we get:
