1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Svetach [21]
1 year ago
7

A JFET has a drain current of 5mA. If IDSS = 10mA and VGS ( off )= -6 v. find The Value Of

Physics
1 answer:
levacccp [35]1 year ago
3 0

\underline {\huge \boxed{ \sf \color{skyblue}Answer :  }}

<u>Given :</u>

\tt \large {\color{purple}     ↬ }  \:  \:  \:  \:  \:  I_{D} = 5mA

\:  \:

\tt \large {\color{purple}     ↬ }  \:  \:  \:  \:  \:  I_{DSS} = 10mA

\:  \:

\tt \large {\color{purple}     ↬ }  \:  \:  \:  \:  \:  V_{GS(off)} = -6V

\:  \:

\tt \large {\color{purple}     ↬ }  \:  \:  \:  \:  \:  V_{GS} =   {?}

\:  \:  \:

<u>Let's Slove :</u><u> </u>

  • \tt \large  I_{D} = I_{(DSS)}  (1 -   \frac {V_{GS}}{V_{GS(off)}} )^{2}

\:  \:  \:

  • \tt \large \: V_{GS} = (1 -  \frac{ \sqrt{I_D} }{ \sqrt{I_{DSS}} } ) \times  V_{GS(off)}

\:  \:  \:

  • \tt \large \: V_{GS} = (1 -  \frac{ \sqrt{5m} }{ \sqrt{10m} } ) \times  { - 6}

\:  \:

  • \underline \color{red} {\tt \large \boxed {\tt V_{GS} = 1.75 ✓}}
You might be interested in
The contact force that acts on objects in a liquid or gas and allows objects to float is called
Harrizon [31]
<span>The contact force that acts on objects in a liquid or gas and allows objects to float is called    </span>Buoyancy.
8 0
3 years ago
Read 2 more answers
Suppose you drive an average of 25 miles a day, for a total of 60 years in a lifetime. The total distance you would have covered
Ahat [919]

The total distance you would have covered is equivalent to going around the earth 22 times.

<h3>Total distance traveled</h3>

The total distance traveled at a given speed and time of motion is calculated as follows;

Distance = speed x time

Distance = \frac{25 \ miles}{day} \times \frac{365 \ days}{1 \ year} \times 60 \ years\\\\Distance = 547, 500 \ miles

<h3>Distance round the Earth</h3>

The distance round the earth or circumference of the earth of the earth has been given as 25,000 miles

<h3>Number of times round the earth</h3>

n = \frac{547,500}{25,000} \\\\ n = 21.9 \ times \ \approx 22 \ times

Thus, the total distance you would have covered is equivalent to going around the earth 22 times.

Learn more about distance here: brainly.com/question/17273444

3 0
2 years ago
A school bus's velocity decreases from 15 m/s to 5 m/s forwards over a period of 10 s. What is the bus's average acceleration? [
aniked [119]

Answer:-1 m/s/s

Explanation:

4 0
3 years ago
5 reasons why people should use electricity wisely​
Bingel [31]

Answer:

1. heating

2. entertainment

3. cooling

4.educational purpose

5.comfort

8 0
3 years ago
A 11.3-kg object oscillates at the end of a vertical spring that has a spring constant of 2.20 ✕ 104 N/m. The effect of air resi
3241004551 [841]

Answer:

(a) the frequency of the dampened oscillation is 7.02 Hz

(b) percentage decrease in amplitude of the oscillation in each cycle is 2%

Explanation:

Given;

mass of the object = 11.3 kg

the spring constant = 2.2 X 10⁴ N/m.

damping coefficient b = 3.00 N · s/m

Part (a) the frequency of the dampened oscillation

The oscillation frequency is calculated as follows;

\omega _D = \sqrt{\omega_o^2 -(\frac{b}{2m})^2}\\\\\omega_o^2 = \frac{k}{m} =\frac{2.2X10^{4}}{11.3} = 1946.903rad/s\\\\thus, \omega _D = \sqrt{1946.903-(\frac{3}{2*11.3})^2} =44.12 rad/s

The damped frequency = \frac{\omega _D}{2\pi } =  \frac{44.12}{2\pi } = 7.02 Hz

Part (b)  percentage decrease in amplitude of the oscillation in each cycle

The amplitude of the oscillation depends on the damping coefficient (b) and period (T), and it is given as;

A(t) = e^{-\frac{b}{2m}(t)}

After one cycle, the amplitude changes from A(t) to A(t+T), where T is the period of the oscillation.

A(t +T) = e^{-\frac{b}{2m}(t+T)}

Percentage decrease in amplitude is gotten by dividing A(t) by A(t+T)

= \frac{e^{-\frac{b}{2m}(t)}}{e^{-\frac{b}{2m}(t+T)}} =e^{-\frac{b}{2m}(T)}

But T = 1/f

Substituting the values of the parameters in the above equation, we will have;

=e^{-\frac{b}{2m}(T)} = e^{-\frac{3}{2X11.3}(\frac{1}{7.02})} = 0.98

Percentage decrease = 1 - 0.98 = 0.02 = 2%

4 0
3 years ago
Other questions:
  • #2 A car accelerates from rest at 4 m/s^2. What is the velocity of the car after 4 second?
    14·1 answer
  • A force of 49N causes a box to move with an acceleration of 7m/s2. Find the mass of the object
    9·1 answer
  • A 160 g basketball has a 32.7 cm diameter and may be approximated as a thin spherical shell. Starting from rest, how long will i
    12·1 answer
  • A car with a total mass of 1800 kg (including passengers) is driving down a washboard road with bumps spaced 4.9 m apart. The ri
    14·2 answers
  • The frequency of a wave is tripled, while the wave speed is held constant. What happens to the wavelength?
    5·2 answers
  • A vaulter holds a 26.90-N pole in equilibrium by exerting an upward force U with her leading hand and a downward force D with he
    7·2 answers
  • In order to be considered an ion, an atom must have a
    12·1 answer
  • Which statement about velocity is true?
    6·1 answer
  • Objects with masses of 165 kg and a 465 kg are separated by 0.340 m. (a) Find the net gravitational force exerted by these objec
    11·1 answer
  • A uniform metal meter-stick is balanced with a 1.0 kg rock attached to the left end of the stick. If the support is located 0.25
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!