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Assoli18 [71]
3 years ago
10

What factors determine the magnitude of the electric force between two particles ?

Physics
2 answers:
Harrizon [31]3 years ago
8 0

Answer: Charge and distance

Explanation:

svp [43]3 years ago
7 0
The electric force between the two particles are calculated through the equation,
 
                          F = kQ₁Q₂ / d²

where F is the force, k is a constant called Coulomb's law constant, Q₁ and Q₂ are the charges, and d is the distance. This equation is called the Coulomb's law. 

It can be seen from the equation above that the electric forces between the objects are majorly affected by the substance's charges and distance. 

The answer to this item is therefore letter A. 
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Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
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5 0
3 years ago
A 0.0140 kg bullet traveling at 205 m/s east hits a motionless 1.80 kg block and bounces off it, retracing its original path wit
makvit [3.9K]

Answer:

Final velocity of the block = 2.40 m/s east.

Explanation:

Here momentum is conserved.

Initial momentum = Final momentum

Mass of bullet = 0.0140 kg

Consider east as positive.

Initial velocity of bullet = 205 m/s

Mass of Block = 1.8 kg

Initial velocity of block = 0 m/s

Initial momentum = 0.014 x 205 + 1.8 x 0 = 2.87 kg m/s

Final velocity of bullet = -103 m/s

We need to find final velocity of the block( u )

Final momentum = 0.014 x -103+ 1.8 x u = -1.442 + 1.8 u

We have

            2.87 = -1.442 + 1.8 u

               u = 2.40 m/s

Final velocity of the block = 2.40 m/s east.

7 0
3 years ago
A student of mass 40kg takes 10s to run up a flight of 50steps. If each step is 15cm high, calculate the Potential Energy of the
astra-53 [7]

Answer:

2943 J

Explanation:

Potential energy = mass x acceleration due to gravity x height in meters

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Substitute the given numbers: (I take acceleration due to gravity as 9.81 m s^-2)

PE = 40 x 9.81 x (0.15x50)

PE = 2943 J

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Explanation:

5 0
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Answer:

the answer is eight(8)

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