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almond37 [142]
3 years ago
14

A rocket sled is tested at "5 g" (5 times the acceleration due to gravity). If the sled starts from rest at position do= 0.00, h

ow long does it take to travel 441 meters? t = _____ s
Physics
2 answers:
stealth61 [152]3 years ago
8 0
D=at²
441m=(5*9.81m/s²)(t²)
t²=441/(5*9.81)
t≈√8.99
t≈3 sec
Tems11 [23]3 years ago
5 0

Answer:

It will take 4.24 seconds to travel 441 meters.

Explanation:

We have equation of motion , s= ut+\frac{1}{2} at^2, s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

In this case the velocity of body in vertical direction = 0 m/s, acceleration = 5g = 5 x 9.8 = 49 m/s^2, we need to calculate time when s = 441 meter.

Substituting

441=0\times t+\frac{1}{2} \times 49\times t^2\\ \\ t = 4.24 seconds

So it will take 4.24 seconds to travel 441 meters.

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In being served, a tennis ball is accelerated from rest to a speed of 31.6 m/s. The average power generated during the serve is
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Answer:

The force acting on the ball is 92.4 N.

Explanation:

Given that,

Initial speed of the ball, u = 0

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W is the work done, W = Fd

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So,

P=F\times v

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F=\dfrac{P}{v}\\\\F=\dfrac{2920\ W}{31.6\ m/s}\\\\F = 92.4\ N

So, the force acting on the ball is 92.4 N. Hence, this is the required solution.

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