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yulyashka [42]
2 years ago
14

What torque will increase angular velocity of a solid cylinder of mass 16 kg and diameter 1 m from zero to 120 rpm in 8 s?

Physics
1 answer:
const2013 [10]2 years ago
7 0
This is what I found online! Hope it helps:)

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A sound source of frequency f moves with constant velocity (less than the speed of sound) through a medium that is at rest. A st
ANTONII [103]

Answer:

The correct answer is d

Explanation:

In this exercise they ask us which statement is correct, for this we plan the solution of the problem, this is a Doppler effect problem, it is the frequency change due to the relative speed between the emitter and the receiver of sound.

The expression for the Doppler effect of a moving source is  

f ’= (v / (v- + v_s) f  

From this expression we see that if the speed the sound source is different from zero feels a change in the  frequency.

The correct answer is d

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3 years ago
Ele is playing with a ball in a bus that moves in a straight line with constant velocity What can you say about the motion of th
cupoosta [38]

Answer:

The ball will fall back and land to Elle's hands.

Explanation:

The bus move in a straight line with constant velocity means that there is no change of direction and no acceleration. Inertia can change the direction of the ball and acceleration can change its velocity. Since these two factors is not present in this scenario, the ball only has vertical movement. Thus the ball will land where it was thrown, in Elle's hands.

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3 years ago
To test the quality of a tennis ball, you drop it onto the floor from a height of 4.00 m. It rebounds to a height of 2.00 m. If
arlik [135]

Answer:

Part a)

a = 1260.3 m/s^2

Part b)

Direction = upwards

Explanation:

When ball is dropped from height h = 4.0 m

then the speed of the ball just before it will strike the ground is given as

v_f^2 - v_i^2 = 2 a d

v_1^2 - 0^2 = 2(9.81)(4.0)

v_1 = 8.86 m/s

Now ball will rebound to height h = 2.00 m

so the velocity of ball just after it will rebound is given as

v_f^2 - v_i^2 = 2 a d

0 - v_2^2 = 2(-9.81)(2.00)

v_2 = 6.26 m/s

Part a)

Average acceleration is given as

a = \frac{v_f - v_i}{\Delta t}

a = \frac{6.26 - (-8.86)}{12.0 \times 10^{-3}}

a = 1260.35 m/s^2

Part B)

As we know that ball rebounds upwards after collision while before collision it is moving downwards

So the direction of the acceleration is vertically upwards

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3 years ago
A material through which electrons can move easily is a what
kirill [66]

Answer:

Electrical conductors

3 0
1 year ago
Pendulum clocks generally run fast in winter and slow in summer
Harman [31]
If the question is true or false then the answer is true
5 0
3 years ago
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