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1 answer:
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Answer:
a) 3.37 x
b) 6.42kg/
Explanation:
a) Firstly we would calculate the volume of the metal using it`s weight in air and water , after finding the weight we would find the density .
Weight of metal in air = 50N = mg implies the mass of metal is 5kg.
Now the difference of weight of the metal in air and water = upthrust acting on it = volume (metal) p (liquid) g = V (1000)(10) = 14N. So volume of metal piece = 14 x
. So density of metal = mass of metal / volume of metal = 5 / 14 x
= 3.37 x
b) Water exerts a buoyant force to the metal which is 50−36 = 14N, which equals the weight of water displaced. The mass of water displaced is 14/10 = 1.4kg Since the density of water is 1kg/L, the volume displaced is 1.4L. Hence, we end up with 3.57kg/l. Moreover, the unknown liquid exerts a buoyant force of 9N. So the density of this liquid is 6.42kg/
Answer:
Explanation:
<u>Sum of Vectors in the Plane</u>
Given two vectors
They can be expressed in their rectangular components as
The sum of both vectors can be done by adding individually its components
If the vectors are given as a magnitude and an angle , each component can be found as
The first vector has a magnitude of 3.14 m and an angle of 30°, so
The second vector has a magnitude of 2.71 m and an angle of -60°, so
The sum of the vectors is
Finally, we compute the magnitude of the sum