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2 years ago

I would like to know how can I practice physics grade 10 questions?

Physics

1 answer:

Vanyuwa [196]2 years ago

6 0

Answer:

Go to K.han Academy and look up High School Physics on there. Other than that You.Tube has some physics curriculums which probably have practice questions. If not you could just pause the video and see if you can answer the questions they're going over yourself. Also, searching up "Physics Worksheet" and such may help.

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When you displace an object from its equilibrium position and the force pushing it back toward equilibrium is _____

hammer [34]

Answer

Linear

Explanation:

4 0

4 years ago

Dennis throws a volleyball up in the air. It reaches its maximum height 1.1\, \text s1.1s1, point, 1, start text, s, end text la

rewona [7]

Answer:

If max height = 1.1 meters, then initial velocity is 3.28 m/s

If max height is 1.1 feet, then the initial velocity is 5.93 ft/s

Explanation:

Recall the formulas for vertical motion under the acceleration of gravity;

for the vertical velocity of the object we have

$v=v_0-g \,t$

for the object's vertical displacement we have

$y-y_0=v_0\,t - \frac{g}{2} \,t^2$

If the maximum height reached by the object is given in meters, we use the value for g in $m/s^2$ which is: $9.8\,\,m/s^2$

If the maximum height of the object is given in feet, we use the value for g in $ft/s^2$ which is : $32\,\,ft/s^2$

Now, when the ball reaches its maximum height, the ball's velocity is zero, so that allows us to solve for the time (t) the process of reaching the max height takes:

$v=v_0-g \,t\\0=v_0-g \,t\\g\,\,t=v_0\\t=\frac{v_0}{g}$

and now we use this to express the maximum height in the second equation we typed:

$y-y_0=v_0\,t - \frac{g}{2} \,t^2\\max\,height=v_0\,(\frac{v_0}{g}) - \frac{g}{2} \,(\frac{v_0}{g})^2\\max\,height= \frac{v_0^2}{2\,g}$

Then if the max height is 1.1 meters, we use the following formula to solve for $v_0$ :

$1.1= \frac{v_0^2}{2\,9.8}\\(9.8)\,(1.1)=v_0^2\\v_0=10.78\\v_0=\sqrt{10.78} \\v_0=3.28\,\,m/s$

If the max height is 1.1 feet, we use the following formula to solve for $v_0$ :

$1.1= \frac{v_0^2}{2\,32}\\(32)\,(1.1)=v_0^2\\v_0=35.2\\v_0=\sqrt{35.2} \\v_0=5.93\,\,ft/s$

5 0

3 years ago

Read 2 more answers

Why do scientist study fossils?

zhuklara [117]

Scientists study fossils of plants, animals, and other organisms in order to better understand what life was like on Earth many years ago and how it has changed over time. Fossils are important evidence for the theory of evolution.

8 0

3 years ago

What statement best describes what it means to maximize your efforts in sports?

Yuliya22 [10]

What statement best describes what it means to maximize your efforts in sports?

D.none of the above

5 0

3 years ago

The force needed to keep a car from skidding on a curve varies jointly as theweight of the car and the square of the car’s speed

Ganezh [65]

Answer:

F' = 251.2 lb

Explanation:

It is given that,

The force needed to keep a car from skidding on a curve varies jointly as the weight of the car and the square of the car’s speed and inversely as the radius of the curve. So,

$F=\dfrac{kWv^2}{r}$