Which expression is equivalent

PLEASE HELP ME WITH NUMBER 11, WORTH 15 POINTS!!! AAAAA

malfutka [58]

Answer: 43.4

Step-by-step explanation: if it was dilated by a bigger number than 1 then it’s goin to have a bigger area and in this case it was dilated by

4 2/3 so you multiply the area by 4 2/3 to round your answer to the nearest tenth and u get 43.4

6 0

3 years ago

Confused on what do do first . Can anyone help ?

kirza4 [7]

So solve for q

first factor q out of the summation $q \sum^{\inf}_{k=2} (\frac{2}{3})^k=8$

now, determine what the summation is
$\sum^{\inf}_{k=2} (\frac{2}{3})^k =?$

its been a while since ive done summations so i dont remember any tricks but that summation is essentially equal to
$\frac{2}{3} ^2 +\frac{2}{3}^3+\frac{2}{3}^4+\frac{2}{3}^5+...$

or factored to be something like this
$\frac{2}{3}^2 *(1+\frac{2}{3}+\frac{2}{3}^2+\frac{2}{3}^3+...)$
which i believe there's a formula for

regardless using a calculator, the summation turns out to be 4/3 i think

you should definitely double check this step

so replacing the summation for 4/3, the equation is now
q*(4/3) =8

pretty easy to solve from here
divide 4/3 to both sides to get q

any questions?

5 0

3 years ago

Pleaseee help me solve this

lapo4ka [179]

Answer:

f(x)=x² +3x-x/2

f(6)=(6)²+3(6)-6/2

= 36 + 18 -3

=51

8 0

4 years ago

Read 2 more answers

If the circle has the same diameter as the edge length of the square, then the area of this circle is ___________the area of the

WINSTONCH [101]

Answer:

The area of this circle is $(\frac{\pi}{2} )$ the area of the square.

For the uniform electric field normal to the surface, the flux through the surface is electric field multiplied by the area of this surface.

Therefore, Φsquare is $(\frac{2}{\pi} )$ ϕcircle

Step-by-step explanation:

Area of the circle is given by;

$A_c = \frac{\pi d^2}{4}$

Area of the square is given by;

$A_s = L^2$

relationship between the edge length of the square, d, and length of its side, L,

$d = \sqrt{L^2 + L^2} \\\\d = \sqrt{2L^2}$

But area of the square , $A_s = L^2$

$d = \sqrt{2A_s}$

Then, the area of the square in terms of the edge length is given by;

$A_s = \frac{d^2}{2}$

Area of the circle in terms of area of the square is given by;

$A_c = \frac{\pi d^2}{4} = \frac{\pi}{2}(\frac{d^2}{2} )\\\\But \ A_s = \frac{d^2}{2} \\\\A_c = \frac{\pi}{2}(\frac{d^2}{2} )\\\\A_c = \frac{\pi}{2}(A_s )$

For the uniform electric field normal to the surface, the flux through the surface is electric field multiplied by the area of this surface.

Ф = E.A

Flux through the surface of the circle is given by;

$\phi _{circle} = E.(\frac{\pi d^2}{4})$

Flux through the surface of the square is given by;

$\phi _{square} = E.(\frac{d^2}{2} )\\\\\phi _{square} =E.(\frac{d^2}{2} ).(\frac{\pi}{2} ).(\frac{2}{\pi} )\\\\\phi _{square} =E.(\frac{\pi d^2}{4} ).(\frac{2}{\pi} )\\\\\phi _{square} =(\phi _{circle}).(\frac{2}{\pi} )$

Therefore, Φsquare is $(\frac{2}{\pi} )$ ϕcircle

5 0

4 years ago

There are 4 red paint cans, 2 green paint cans, and 1 yellow paint can. What is the probability of choosing a yellow paint can t

Sophie [7]

The probability of those sequence of events is 2/21

5 0

3 years ago