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Elina [12.6K]
2 years ago
7

Sahil chooses a number, divides it by 8 , adds 8 to the answer. Then multiples the answer with 8 . He obtains the result as 952

. The number he chooses in the beginning was
I'M IN LOVE WITH A FAIRYTALE
EVEN THOUGH IT HURTS
CAUSE I DON'T CARE IF I LOOSE MY MIND
I'M ALREADY CURSED ​
Mathematics
1 answer:
Georgia [21]2 years ago
5 0

Answer:

888

Step-by-step explanation:

let the number be n then divide by 8 , that is \frac{n}{8}

now add 8 to this

\frac{n}{8} + 8 and finally multiply this by 8 and equate to 952

8(\frac{n}{8} + 8) = 952 ( divide both sides by 8 )

\frac{n}{8} + 8 = 119 ( subtract 8 from both sides )

\frac{n}{8} = 111 ( multiply both sides by 8 to clear the fraction )

n = 888

the number chosen was 888

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Please help!! I will make you brainlest.
Strike441 [17]

Answer:

Step-by-step explanation:

These problems are based on triangle ratios. You cannot use the Pythagorean theorem to solve them.

The first triangle is a 45 45 90 degree triangle (I'm talking about the angles), and so, the ratio is 1:1:\sqrt{2\\}, so I have to divide the hypotenuse by \sqrt{2\\} to get the legs. The hypotenuse is 15\sqrt{6}, so that divided by \sqrt{2\\} is 15\sqrt{3\\}. X is the same length as y because of the triangle ratio, so both x and y for the first triangle are 15\sqrt{3\\}.

The second triangle is a 30 60 90 degree triangle, so the ratio is x:x\sqrt{3}:2x. The short leg is 7\sqrt{3}, so 7\sqrt{3} * 2 is the hypotenuse, which is 14\sqrt{3}. The long leg is 7\sqrt{3} * \sqrt{3}, which is 21. So, x for the second triangle is 14\sqrt{3}, and y for the second triangle is 21.

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What is the range of the function {(0, 15), (4, 6), (6, 4), (8, 0)}?
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The range of a function is the set of output values of the function

The range of the function is: {15, 6, 4, 0}

<h3>How to determine the range</h3>

The function is defined as:

(x,y) =  {(0, 15), (4, 6), (6, 4), (8, 0)}

The range is the y-values.

So, we have:

y = {15, 6, 4, 0}

Hence, the range of the function is: {15, 6, 4, 0}

Read more about range at:

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disa [49]

Answer:

\displaystyle  a_{n}  =     (2)^{2n -1}   -   (3) ^{n-1 }

Step-by-step explanation:

we want to figure out the general term of the following recurrence relation

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we are given a linear homogeneous recurrence relation which degree is 2. In order to find the general term ,we need to make it a characteristic equation i.e

  • {x}^{n}  =  c_{1} {x}^{n - 1}  + c_{2} {x}^{n - 2}  + c_{3} {x}^{n -3 } { \dots} + c_{k} {x}^{n - k}

the steps for solving a linear homogeneous recurrence relation are as follows:

  1. Create the characteristic equation by moving every term to the left-hand side, set equal to zero.
  2. Solve the polynomial by factoring or the quadratic formula.
  3. Determine the form for each solution: distinct roots, repeated roots, or complex roots.
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Step-1:Create the characteristic equation

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so substitute the roots we got:

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\displaystyle \boxed{ a_{n}  =    (2)^{2n-1 }   -   (3) ^{n -1}}

and we're done!

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