9514 1404 393
Answer:
156 cm³
Step-by-step explanation:
The volume of any prism is the product of the base area and the height of the prism. Here, we can take the "base" to be the front face of the assembly, and its "height" to be the 3 cm distance between the front and back faces.
The front face area is the sum of the triangle area and the rectangle area.
A = 1/2bh + LW
A = (1/2)(10 cm)(4 cm) + (16 cm)(2 cm) = 52 cm²
Then the volume is ...
V = Bh = (52 cm²)(3 cm) = 156 cm³ . . . . total volume of the two blocks
The height of broken part of tree from ground is 5.569m.
Justification:
Let BD is a tree of height 12 m.
<u>Suppose it got bent at a point C and let the part CD take the position CA, meeting the ground at A</u>.
i.e., CD = AC = h m
<u>Broken part makes 60° angle from ground</u>
So, ∠BAC = 60°
<u>Now, height of remaining part of tree</u> = (12 – h)m.
In right angled ∆ABC,
sin 60° = BC/AC
⇒ √3/2 = (12 - h)/h
⇒ √3h = 2(12 – h)
⇒ √3h = 24 – 2h
⇒ √3h + 2h = 24
⇒ h(√3 + 2) = 24
⇒ h(1.732 + 2) = 24
⇒ h(3.732) = 24
⇒ h = 24/3.732 = 6.4308 m
<u>Hence, height of broken tree from ground</u>
⇒ BC = 12 – h
⇒ 12 – 6.4308 = 5.569m
<u>Hence, tree is broken 5.569 m from ground</u>.
<u>Note</u>: See attached picture.
Answer:
she added 11 plus 10 wrong
Step-by-step explanation:
11 plus 10 = 21
Answer:
i have no idea but if i had to guess it would be around -3.00k or -4.00k
Step-by-step explanation: