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kupik [55]
2 years ago
8

During radioactive beta-decay, a neutron (1.6749x10-27 kg) at rest decays into a very slow moving proton (1.6726x10-27 kg) and a

fast electron (9.109x10-31 kg). What is the speed of the electron? (Hint: find the total energy of the electron)
Physics
1 answer:
Ne4ueva [31]2 years ago
3 0

The speed of the electron emitted in the radioactive beta-decay is determined as 2.186 x 10⁶ m/s.

<h3>Speed of electron </h3>

The speed of the electron is determined from the total energy of the electron.

Assuming the emitted electrons are in first energy level, E = 13.6 eV

K.E = ¹/₂mv²

v² = 2K.E/m

v² = (2 x 13.6 x 1.6 x 10⁻¹⁹)/(9.11 x 10⁻³¹)

v² = 4.777 x 10⁻¹²

v = 2.186 x 10⁶ m/s

Learn more about speed of electrons here: brainly.com/question/12889606

#SPJ1

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2. The components of vector A are given as follows:
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Answer:

50 degree.

Explanation:

Given that the components of vector A are given as follows: Ax = 5.6 Ay = -4.7

The angle between vector A and B in the positive direction of x-axis will be achieved by using the formula:

Tan Ø = Ay/Ax

Substitute Ay and Ax into the formula above.

Tan Ø = -4.7 / 5.6

Tan Ø = -0.839

Ø = tan^-1(-0. 839)

Ø = - 40 degree

Therefore, the angle between vector A and B positive direction of x-axis will be

90 - 40 = 50 degree.

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3 years ago
The depth of a circular well is 5m. water level is below 2m from the upper face of the wall. Find the pressure at its base ? (g=
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7m

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Which statements describe Rutherford model of the atom
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3 years ago
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Earthquakes <br> Shaking of the ground <br> Seismographs <br> Scientific method
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3 years ago
A car of mass 1500 kg travels due East with a constant speed of 25.0 m/s. Eventually it turns right, and travels due South with
e-lub [12.9K]

Answer:

The direction of the car’s change in linear momentum is 149.04° West of North

Explanation:

Momentum is defined as the product of mass of a body and its velocity

Momentum = mass × velocity

Change in Momentum = mass × change in velocity

∆P = m∆v

∆P = m(v-u)

Given m = 1500kg

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u = 15m/s

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Since the car first travels due East i.e +x direction

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θ = tan^-1(y/x)

θ = tan^-1(-15/25)

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Since tan is negative in the second quadrant

θ = 180-30.96

θ = 149.04°

The direction of the car’s change in linear momentum is 149.04° West of North

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4 years ago
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