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STatiana [176]
3 years ago
7

2. The components of vector A are given as follows:

Physics
1 answer:
Stella [2.4K]3 years ago
3 0

Answer:

50 degree.

Explanation:

Given that the components of vector A are given as follows: Ax = 5.6 Ay = -4.7

The angle between vector A and B in the positive direction of x-axis will be achieved by using the formula:

Tan Ø = Ay/Ax

Substitute Ay and Ax into the formula above.

Tan Ø = -4.7 / 5.6

Tan Ø = -0.839

Ø = tan^-1(-0. 839)

Ø = - 40 degree

Therefore, the angle between vector A and B positive direction of x-axis will be

90 - 40 = 50 degree.

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4 years ago
What is the difference between kinetic and potential energy and how do they work?
Iteru [2.4K]

To explain, I will use the equations for kinetic and potential energy:

PE = mgh\\KE = \frac{1}{2}mv^{2}

<h3>Potential energy </h3>

Potential energy is the potential an object has to move due to gravity.  An object can only have potential energy if 1) <u>gravity is present</u> and 2) <u>it is above the ground at height h</u>.  If gravity = 0 or height = 0, there is no potential energy.  Example:

An object of 5 kg is sitting on a table 5 meters above the ground on earth (g = 9.8 m/s^2).  What is the object's gravitational potential energy?  <u>(answer: 5*5*9.8 = 245 J</u>)

(gravitational potential energy is potential energy)

<h3>Kinetic energy</h3>

Kinetic energy is the energy of an object has while in motion.  An object can only have kinetic energy if the object has a non-zero velocity (it is moving and not stationary).  An example:

An object of 5 kg is moving at 5 m/s.  What is the object's kinetic energy?  (<u>answer: 5*5 = 25 J</u>)

<h3>Kinetic and Potential Energy</h3>

Sometimes, an object can have both kinetic and potential energy.  If an object is moving (kinetic energy) and is above the ground (potential), it will have both.  To find the total (mechanical) energy, you can add the kinetic and potential energies together.  An example:

An object of 5 kg is moving on a 5 meter table at 10 m/s.  What is the objects mechanical (total) energy?  (<u>answer: KE = .5(5)(10^2) = 250 J; PE = (5)(9.8)(5) = 245 J; total: 245 + 250 = 495 J</u>)

7 0
3 years ago
If you have to stop on an incline, your stopping distance will be __________ on a flat surface.
Nataliya [291]
Not as far on a flat surface
5 0
4 years ago
A guitar string is 90 cm long and has a mass of 3.5g . The distance from the bridge to the support post is L=62cm, and the strin
nataly862011 [7]

Answer:

v_1 =  301 Hz

v_2 =  601 \ \ Hz

v_3 =  901 \ Hz

Explanation:

From the question we are told that

     The  length of the string is  l = 90 \ cm  =  0.9 \ m

     The mass of the string is  m_s  =  3.5 \ g =0.0035 \ kg

     The  distance  from the bridge to the support post L =  62 \ c m  =  0.62 \ m

    The tension is T  =  540 \ N

Generally the frequency is mathematically represented as

        v  =  \frac{n}{2 * L }  [\sqrt{ \frac{T}{\mu} } ]

Where n is and integer that defines that overtones

i.e  n =   1 is for fundamental frequency

      n =  2   first overtone

       n =3   second overtone

Also  \mu is the linear density of the string which is mathematically represented as

           \mu  =  \frac{m_s}{l}

=>        \mu  =  \frac{0.0035 }{ 0.9 }

=>       \mu  =  0.003889 \  kg/m

So for   n = 1

     v_1  =  \frac{1}{2 *  0.62 }  [\sqrt{ \frac{ 540}{0.003889} } ]

     v_1  = 301 \ Hz

So for  n =  2

     v_2  =  \frac{2}{2 *  0.62 }  [\sqrt{ \frac{ 540}{0.003889} } ]

     v_2  = 601 \ Hz

So for  n =  3

     v_3  =  \frac{3}{2 *  0.62 }  [\sqrt{ \frac{ 540}{0.003889} } ]

     v  =901  \ Hz

     

       

5 0
4 years ago
What is the kinetic energy of a 1 kg pie if it is thrown at 10 m/s?
nignag [31]

Given

mass (m) = 1 kg

velocity (v) = 10 m/s

kinetic energy ( ke) = ?

,we know

K.E =1/2 m v²

= 1/2 * 1 * 10²

= 100/2

=50 joule

hope it helps :)

7 0
3 years ago
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