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2 years ago

Given that

Mathematics

1 answer:

fiasKO [112]2 years ago

5 0

The ratio of a : b : c in its simplest form is 5 : 12 : 30 respectively

<h3>How to solve ratio?</h3>

a : c = 1 : 6
b : c = 2 : 5

So,

a / b = 1/6

b/c = 2/5

lowest common multiple of c in both ratio

1/6 + 2/5

=(5 + 12) /30

a : b and b : c

= 5/30 and 12/30

Therefore,

a : b : c = 5 : 12 : 30

Learn more about ratio:

brainly.com/question/2328454

#SPJ1

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Finding an Equation of a tangent Line in Exercise, find an equation of the tangent line to the graph of the function at the give

frutty [35]

Answer:

$y=\dfrac{3x}{e}+\dfrac{4}{e}$

this is the equation of the tangent at point (-1,1/e)

Step-by-step explanation:

to find the tangent line we need to find the derivative of the function g(x).

$g(x) =e^{x^3}$

we know that $\frac{d}{dx}(e^{f(x)})=e^{f(x)}f'(x)$

$g'(x) =e^{x^{3}}(3 x^{2})$

$g'(x) =3 x^{2} e^{x^{3}}$

this the equation of the slope of the curve at any point x and it also the slope of the tangent at any point x. hence, g'(x) can be denoted as 'm'

to find the slope at (-1,1/e) we'll use the x-coordinate of the point i.e. x = -1

$m =3 (-1)^{2} e^{(-1)^{3}}\\m =3e^{-1}\\m=\dfrac{3}{e}$

using the equation of line:

$(y-y_1)=m(x-x_1)$

we'll find the equation of the tangent line.

here (x1,y1) =(-1,1/e), and m = 3/e

$(y-\dfrac{1}{e})=\dfrac{3}{e}(x+1)\\y=\dfrac{3x}{e}+\dfrac{3}{e}+\dfrac{1}{e}\\$

$y=\dfrac{3x}{e}+\dfrac{4}{e}$

this is the equation of the tangent at point (-1,1/e)

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3 years ago

Solve equation s - 12= 20. s=?

svetlana [45]

Answer:

s-12=20

:. 20+12=s

20+12=32

<h2>your answer is 32</h2><h2>s=32</h2>

Step-by-step explanation:

<h2>hope its fine buddy</h2>

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