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Artist 52 [7]
3 years ago
8

What is a measurement of the amount of solute that is dissolved in a given quantity of solvent?

Chemistry
2 answers:
weqwewe [10]3 years ago
6 0
B.concentration is the answer 

almond37 [142]3 years ago
3 0

Answer:

B

Explanation: The answer is B: concentration.

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How many grams of sodium oxide can be synthesized from 17.4 g of sodium? assume that more than enough oxygen is present. the bal
Tatiana [17]
Equation is as follow,

<span>                          4 Na (s)  +  O</span>₂ <span>(g)    →    2Na</span>₂<span>O (s)

According to equation,

      91.92 g (4 moles) of Na produces  =  123.92 g (2 moles) of Na</span>₂O
So,
                    17.4 g of Na will produce  =  X g of Na₂O

Solving for X,
                                   X  =  (17.4 g × 123.92 g) ÷ 91.92 g

                                   X  =  23.45 g of Na₂O
7 0
3 years ago
What is the mass number of 207Pb ? A: 289 B: 207 C: 125 D: 82
Sergio [31]
207 is the mass number. 82 would be the atomic number
3 0
3 years ago
When one material is rubbed against another, electrons jump readily from one to the other. why don’t protons do that?
Pachacha [2.7K]
Protons are held inside nucleous with neutrons with large amount of force. So mere rubbing doesn't help in breaking the nucleous of an atom. But electrons are far from the nucleous and the force of attraction is smaller. So electrons can jump readily while protons can't
5 0
3 years ago
The force of gravity always pulls ____
damaskus [11]
Down...
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6 0
3 years ago
Carbon-14 is a radioactive isotope that decays according to first-order kinetics in a process that has a half-life of 5730 years
Sliva [168]

Answer : The time passed in years is 2.83\times 10^3\text{ years}

Explanation :

Half-life = 5730 years

First we have to calculate the rate constant, we use the formula :

k=\frac{0.693}{t_{1/2}}

k=\frac{0.693}{5730\text{ years}}

k=1.21\times 10^{-4}\text{ years}^{-1}

Now we have to calculate the time passed.

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 1.21\times 10^{-4}\text{ years}^{-1}

t = time passed by the sample  = ?

a = let initial amount of the reactant  = X g

a - x = amount left after decay process = 71\% \times (x)=\frac{71}{100}\times (X)=0.71Xg

Now put all the given values in above equation, we get

t=\frac{2.303}{1.21\times 10^{-4}}\log\frac{X}{0.71X}

t=2831.00\text{ years}=2.83\times 10^3\text{ years}

Therefore, the time passed in years is 2.83\times 10^3\text{ years}

8 0
3 years ago
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