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EleoNora [17]
3 years ago
5

If the solubility of a gas is 10.5 g/L at 650 kPa pressure, what is the solubility of the gas when the pressure is 200 kPa? Show

your work.
Chemistry
1 answer:
Leni [432]3 years ago
5 0

Answer: 3.23 g/L

Explanation:  

P1= 650 kPa

P2= 200 kPa

S1= 10.5 g/L

S2= ?    

S2 = P2 x S1/P1  

S2 = ( 200 kPa x 10.5 g/L)/(650 kPa)

S2 = 3.23 and since we are looking for the solubility of the gas when the pressure is 200 kPa, so we use g/L, 3.23 g/L.

Hope this helped! :)

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Consider these elements: p, ca, si, s, ga.<br> a. write the electron configuration for each element
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Method:

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<span>
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7 0
3 years ago
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Karolina [17]

Answer:

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Hope this helps

6 0
2 years ago
Read 2 more answers
Explain how you can use boyle's law to determine the new volume of gas when its pressure is increased from 270 kPa to 540 kPa? T
LUCKY_DIMON [66]
There are several information's already given in the question. Based on the information's the answer can be easily deduced. 

We know the formula

<span>P1*V1/T1 = P2*V2/T2
</span>
As the temperature is constant, so T1 and T2 can be negated. The formula changes to 
<span>P1*V1 = P2*V2
</span>70 * 1 = 540 * V2
270/540 = V2
<span>V2 = 0.5
</span>
From the above deduction, we can conclude that the new volume is 0.5 liters. I hope that the procedure is clear enough for you to understand.
7 0
3 years ago
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