Question

If the solubility of a gas is 10.5 g/L at 650 kPa pressure, what is the solubility of the gas when the pressure is 200 kPa? Show your work.

Answer 1

Answer: 3.23 g/L

Explanation:  

P1= 650 kPa

P2= 200 kPa

S1= 10.5 g/L

S2= ?    

S2 = P2 x S1/P1  

S2 = ( 200 kPa x 10.5 g/L)/(650 kPa)

S2 = 3.23 and since we are looking for the solubility of the gas when the pressure is 200 kPa, so we use g/L, 3.23 g/L.

Hope this helped! :)