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3 years ago

What grey rock that has crinoids and brachiopods reacts to hydrochloric acid?

2 answers:

6 0

Hey there Barney456,

What grey rock that has Crinoids and Brachiopods reacts to Hydrochloric acid?

Answer:

Limestone. It is found underwater. When marine organisms die their skeletons compact and form the limestone

Hope this helps :D

~Danielle♥

Anon25 [30]3 years ago

5 0

The rock is limestone, I hope this helps!!

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A pH of 3 is how many times more acidic than a pH of 6?

nika2105 [10]

Answer:

A pH=3 is 1000 times as acidic as a pH=6.

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3 years ago

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How we can preserve the wetlands areas of nepal?

Luden [163]

Answer:

Reduce, reuse, and recycle your waste and trash. Protecting the environment helps protect the wetlands, especially since trash can make its way into the water. The best and easiest way to protect the environment is by limiting your household waste.

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3 years ago

4. Magnesium and oxygen undergo a chemical reaction to

erastovalidia [21]

Answer:

About 16.1 grams of oxygen gas.

Explanation:

The reaction between magnesium and oxygen can be described by the equation:
$\displaystyle 2\text{Mg} + \text{O$_2$} \longrightarrow 2\text{MgO}$

24.4 grams of Mg reacted with O₂ to produce 40.5 grams of MgO. We want to determine the mass of O₂ in the chemical change.

Compute using stoichiometry. From the equation, we know that two moles of MgO is produced from every one mole of O₂. Therefore, we can:

Convert grams of MgO to moles of MgO.
Moles of MgO to moles of O₂
And moles of O₂ to grams of O₂.

The molecular weights of MgO and O₂ are 40.31 g/mol and 32.00 g/mol, respectively.

Dimensional analysis:

$\displaystyle 40.5\text{ g MgO} \cdot \frac{1\text{ mol MgO}}{40.31\text{ g MgO}} \cdot \frac{1\text{ mol O$_2$}}{2\text{ mol MgO}} \cdot \frac{32.00\text{ g O$_2$}}{1\text{ mol O$_2$}} = 16.1\text{ g O$_2$}$

In conclusion, about 16.1 grams of oxygen gas was reacted.

You will obtain the same result if you compute with the 24.4 grams of Mg instead:

$\displaystyle 24.4\text{ g Mg}\cdot \frac{1\text{ mol Mg}}{24.31\text{ g Mg}} \cdot \frac{1\text{ mol O$_2$}}{1\text{ mol Mg}} \cdot \frac{32.00\text{ g O$_2$}}{1\text{ mol O$_2$}} = 16.1\text{ g O$_2$}$

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2 years ago

How many oxygen are present in 2.50 mol of oxygen atoms?

Colt1911 [192]

I want to talk to you girl?

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3 years ago

300 grams of a compound which contains only carbon, hydrogen and oxygen is analyzed and found to contain the exact same percenta

ser-zykov [4K]

The empirical formula of the compound is C₄H₅O₃.

Explanation:

If hydrogen % = 5.98823, the Sum of C+O = 94.01177% or 47.005885% each

The original mass of 300 g is not important

C = 47.005885 / 12.011 = 3.913569

H = 5.98823 / 1.008 = 5.94070

O = 47.005885 / 15.999 = 2.93805

Divide by the smallest number:

C =1.33

H = 2.022

O = 1

Multiply through by 3

C = 4

H =6

O = 3

The empirical formula of a compound = C₄H₆O₃

Do not be confused by the 300 g. It is totally irrelevant to the question because you are dealing with % amounts. It would only have been of importance if you were given some mass values.

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3 years ago