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myrzilka [38]
2 years ago
7

What is the name of cuo? explain how you determined the bond type and the steps you used to determine the naming convention for

the compound.
Chemistry
1 answer:
skelet666 [1.2K]2 years ago
5 0

The name of CuO is Copper(II) oxide have the two most common oxidation states of copper are +2 and +1.

<h3>What is copper oxide used for?</h3>

Copper oxide is a trace element for the zootechnical and agricultural sector. Cupric oxide is also used as a raw material for the production of catalysts and pigments in the field of ceramics, glass and plastics.

This compound makes two different types of bonds being the hydrogen bond when it's a hydrogen and covalent bond when we have an oxygen or a nitrogen.

See more about Copper(II) oxide at brainly.com/question/24217869

#SPJ1

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If an atom of the following element had a neutral charge, how many electrons would it have?
Yakvenalex [24]

Answer:

31

Explanation:

In order for an atom to have a neutral charge, it needs to have the same number of protons and electrons. You can see by the illustration that the atomic number is 31, so this element has 31 protons. Knowing that, we also know that it must have 31 electrons to be neutral.

8 0
3 years ago
A patient receives 3.3 L of glucose solution intravenously (IV). If 100. mL of the solution
artcher [175]

Answer:

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Explanation:

The question is missing the concentration of the glucose solution. Standard glucose concentration for IV solution is 5% or 5g of glucose every 100mL of solution.  

We need to determine how many grams of glucose are there inside the solution. The number of glucose in 3.3L solution will be:  

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6 0
4 years ago
The solution you identified in question (1) acts as a buffer due to reactions that occur within the solution when an acid or a b
weeeeeb [17]

Answer:

The answer is "\bold{CH_3COO^{-} \ (aq) + H^{+}\ (aq) \longrightarrow CH_3COOH \ (aq)}"

Explanation:

When HCI is added in the chemical equation it reacts with sodium acetate so, it will give the following chemical equation:

CH_3COONa\ (aq) + HCl\ (aq)\longrightarrow CH_3COOH\ (aq) + NaCl\ (aq)\\\\

 In this, the CH_3COOH is a weak acid so, it not completely dissociated.

CH_3COONa \ (aq) \ \ and \ NaCl were strong electrolytes they are completely dissociated.

The HCl is a strong acid so, it is completely dissociated So, the net ionic equation is:

CH_3COO^{-} \ (aq) + H^{+}\ (aq) \longrightarrow CH_3COOH \ (aq)

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