calculate the work done in kilo joules in lifting a mass of 20kg at steady velocity through a vertical height of 20m
1 answer:
Answer:

Explanation:
Since work done is in the form of potential energy, we will use the formula of potential energy here.
We know that,
<h3>P.E. = mgh </h3>
Where,
m = mass = 20 kg
g = acceleration due to gravity = 10 m/s²
h = vertical height = 20 m
So,
<h3>Work done = mgh</h3>
Work done = (20)(10)(20)
Work done = 4000 joules
Work done = 4 kJ
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
You might be interested in
Answer:
The third image
Explanation:
The one with the thumb pointing to the right
The lateral displacement is I don’t know tbh I think 16.8
Answer:
IT doesnt push down because the lawnmower has wheels and the ground is hard
Explanation:
Branliest
Not sure... need help with it
25km/h = 6.94 m/s
suvat
s=16
u=6.94
v=0
a=a
v^2=u^2+2as
(v^2-u^2)/2s = a =1.5ms^-2