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pav-90 [236]
1 year ago
13

calculate the work done in kilo joules in lifting a mass of 20kg at steady velocity through a vertical height of 20m

Physics
1 answer:
bulgar [2K]1 year ago
5 0

Answer:

\huge\boxed{\sf Work\ done = 4 kJ}

Explanation:

Since work done is in the form of potential energy, we will use the formula of potential energy here.

We know that,

<h3>P.E. = mgh </h3>

Where,

m = mass = 20 kg

g = acceleration due to gravity = 10 m/s²

h = vertical height = 20 m

So,

<h3>Work done = mgh</h3>

Work done = (20)(10)(20)

Work done = 4000 joules

Work done = 4 kJ

\rule[225]{225}{2}

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A garden hose attached with a nozzle is used to fill a 10‐ gal bucket. The inner diameter of the hose is 2 cm, and it reduces to
nadya68 [22]

Answer:

Explanation:

Given

Volume of bucket V=10\ gallon

Time taken to fill the bucket t=50\ s

so volume flow rate is \dot{V}=\frac{10}{50}=0.2\ gal/s

1 gal is equivalent to 0.133\ ft^3

\dot{V}=0.0267\ ft^3/s

mass flow rate \dot{m}=\rho \times \dot{V}

\dot{m}=62.4\times 0.0267

\dot{m}=1.668\ lbs

(b)Average velocity through nozzle exit

\dot{V}=Av_{avg}

v_{avg}=\dfrac{0.0267}{\frac{\pi}{4}\times (0.0262)^2}

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8 0
3 years ago
light waves with a frequency of 7.26 x 10^14 HZ lies in the violet region of the visible spectrum. what is the wavelength of thi
pogonyaev

Answer:

4.13×10⁻⁷ m

Explanation:

Applying

v = λf................... Equation 1

Wherfe v = speed of light, λ = wavelength of light, f = frequency of light.

make λ the subject of the equation

λ = v/f....................... Equation 2

Note: Light is an electromagnetic wave, and all electromagnetic wave moves with thesame speed which is 3×10⁸ m/s.

From the question,

Given: f = 7.26×10¹⁴ Hz

Constant: v = 3×10⁸ m/s

Substitute these values into equation 2

λ = (3×10⁸)/(7.26×10¹⁴)

λ = 4.13×10⁻⁷ m

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