Answer:OB=58.3m
Explanation:
So here cow wanders 30m in north and turns 22 degrees in right side and moves 40m more, as shown in figure given.
now take the starting point as a origin such that cow moves in x-y co-ordinate axis.
As shown in figure length OA is the length when cow moves in north or y direction. Later she takes 22 degrees turn to right and moves 40m more.
So the final displacement is the length of cow from the origin that is length OB.
now co-ordinates of B are [40cos22°,40sin22°+30] i.e [37.084,44.984]
now displacement of cow= length of OB
= ![\sqrt{[37.084]^{2}+[44.984]^{2} }](https://tex.z-dn.net/?f=%5Csqrt%7B%5B37.084%5D%5E%7B2%7D%2B%5B44.984%5D%5E%7B2%7D%20%20%7D)
=
OB =
Answer:

Explanation:
Initial potential energy of the given spacecraft is given as

so we have

so we have






now total work done to move it to infinite is given
W = 0 - U

ANSWER:
d. remains a non-zero constant.
STEP-BY-STEP EXPLANATION:
If we consider that there is no air resistance and that the horizontal component would be at x, the velocity remains a non-zero constant
Answer:
To obtain the power, we first need to find the work made by the force.
1) To calculate the work, we need the next equation:

So the force is given by the problem so our mission is to find 'dx' in terms of 't'
2) we know that:

So we have:

Then:

3) Finally, we replace everything:

After some calculation, we have as a result that the work is:
161.9638 J.
4) To calculate the power we need the next equation:

So
P = 161.9638/4.7 = 34.46 W
Answer:
El peso es de 882 newton.
Explicación:
El helicóptero se detiene a la altura en la que volaba para dejar caer una caja de 90 kg al suelo, el peso de la caja llega hasta los 882 Newton porque el peso es una fuerza dirigida hacia el centro de la tierra y depende de la gravedad. La fórmula del peso es multiplicar la masa por la gravedad, de modo que cuando se multiplican 90 kg de masa por 9,8 metros / seg2, obtenemos el peso del objeto que es 882 newton.