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Semenov [28]
3 years ago
15

A 13,000 kg helicopter accelerates upward a 0.5 m/s^2 while lifting a 2000 pound car. to the nearest newton, what is the lift fo

rce exerted by the air on the rotors? use 4.45 n = 1 lb.
Physics
1 answer:
Vinil7 [7]3 years ago
8 0

Lift force exerted by the air on the rotors=143244 N

Explanation:

we use Newtons second law

F- (M+m)g=(M+m)a

F= lift force

m= mass of helicopter= 13000 Kg

M= mass of car= 2000 lb=907.2 kg

a= acceleration= 0.5 m/s²

g= acceleration due to gravity

F- (M+m)g=(M+m)a

F=(M+m)(a+g)

F=(13000+907.2)(0.5+9.8)

F=143244 N

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Why do you keep moving forward when you slam on the brakes of your bike?
g100num [7]
Because the act of braking is an example of negative acceleration.
Example: if the rate of braking was say 2 meters per second^2, and the starting velocity was 10 m/s, it would take 5 seconds to come to a stop(during those 5 seconds you would still be moving).
6 0
3 years ago
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Define solar system.<br>Mention 3 types of energy.​
sveticcg [70]

Answer:

The Solar System is the Sun and all the objects that orbit around it

The Sun is orbited by planets, asteroids, comets and other things. ...

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4 0
2 years ago
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Zeros are always considered significant digits when they are to the left of the decimal point
maksim [4K]

Answer:

Zeros to the left of a decimal can be insignificant place holders, such as in 0.043 (two significant figures).

They can be significant if they are between two digits who themselves are significant, such as in 101.000 (three significant figures).

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7 0
3 years ago
Speakers A and B are vibrating in phase. They are directly facing each other, are 6.69 m apart, and are each playing a 75.0-Hz t
maw [93]

Answer:

3.117 m

Explanation:

Given that:

the distance of separation between speaker A and speaker B (L) = 6.69 m

Frequency (F) = 750 -Hz tone

Velocity of speed of sound = 343 m/s

The distance from Speaker A to the first point (L₁) on the line can be calculated by using the formula:

L_1=\frac{L-A}{2}

where A = \frac{Velocity ofthe sound (V)}{Frequency (F)}

we have:

L_1=\frac{L-\frac{V}{F} }{2}

L_1=\frac{6.69-\frac{343}{750} }{2}

L_1=\frac{6.69-0.457 }{2}

L_1=\frac{6.233 }{2}

L_1= 3.1165 m

L_1=3.117 m

∴ the distance from speaker A to the first point on the line between the speakers where constructive interference occurs = 3.117 m

3 0
3 years ago
What is the velocity vector of a particle traveling to the right along the hyperbola y=x^-1 with a constant speed 5cm/s when the
Ronch [10]
:<span>  </span><span>The gradient of the curve 1/x at x=2 is m = -¼ 
We may choose any length of line to represent the direction of the slope (direction vector) at that point. We could choose a line for which x = 2 and then y would have to be -½ so that the gradient is still = -½/2 = -¼. It is simply convenient to choose a unit length for x, making y = -¼ The length of the resultant of x and y is √(1²+¼²) = √(17/16) = √(17)/4 which is a direction vector. If we had taken the direction vector to be (2, ½) then we would have a resultant direction vector of √17/2. It doesn't really matter what length the direction vector is - it's job is only to show the direction. So their choice of 1 is quite arbitrary but convenient, since it is easy to work with units – that's why we use units! 
Now, we know that the magnitude of the velocity vector must be 5 and the magnitude of our direction vector at the moment is √(17)/4. We therefore need to multiply this direction vector by 20/√(17) to get 5 – just try it : √(17)/4 × 20/√(17) = 5. 

We could equally well have done this with (2, ½) and would have got 2½ for lambda.</span>
3 0
2 years ago
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