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Leokris [45]
3 years ago
12

If a car travels 200 m to the east in 8.0s what is the car's average velocity.

Physics
1 answer:
OleMash [197]3 years ago
3 0

Answer:

25mph

Explanation:

you do distance divided by time. 200/8=25

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What is an example of kinetic energy
Olenka [21]

An airplane has a large amount of kinetic energy in flight due to its large mass and fast velocity.

6 0
3 years ago
What is the surface area to volume ratio of this cube
tamaranim1 [39]

I can't see that cube from here.

But if the length of the side of the cube is ' K ' units,
then the surface area of the cube is  6K² units², and
the volume of the cube is  K³ units³.

The ratio of the surface area to the volume is

               (6K² units²) / (K³ units³)  =  (6) / (K units) .

So for example, if the side of the cube is 2 inches, then
the ratio of surface area to volume is  "3 per inch".

That's the answer.  I did the whole thing in order to earn
the points, but I don't expect you to understand much of it,
because I see from your username that you suck at math.
I'm sorry you decided that.  Now that you've put up the
brick wall, it'll be even harder for any math to find its way
in there, and you'll miss out on a lot of the fun.

3 0
3 years ago
The maximum wavelength an electromagnetic wave can have and still eject an electron from a copper surface is 264 nm .What is the
Tamiku [17]

Answer:

4.71 eV

Explanation:

For an electromagnetic wave with wavelength

\lambda=264 nm = 2.64\cdot 10^{-7} m

the energy of the photons in the wave is given by

E=\frac{hc}{\lambda}=\frac{(6.63\cdot 10^{-34}Js)(3\cdot 10^8 m/s)}{2.64\cdot 10^{-7}m}=7.53\cdot 10^{-19} J

where h is the Planck constant and c the speed of light. Therefore, this is the minimum energy that a photon should have in order to extract a photoelectron from the copper surface.

The work function of a metal is the minimum energy required by the incident light in order to extract photoelectrons from the metal's surface. Therefore, the work function corresponds to the energy we found previously. By converting it into electronvolts, we find:

E=\frac{7.53\cdot 10^{-19} J}{1.6\cdot 10^{-19} J/eV}=4.71 eV

3 0
3 years ago
If the magnitude of vector A⃗ is less than the magnitude of vectorB⃗ , then the x component of A⃗ is less than the x component o
Mama L [17]
It’s true because..yeah
5 0
3 years ago
A charge Q is to be divided into two parts, labeled 'q' and 'Q-q? What is the relationship of q to Q if, at any given distance,
Lisa [10]

Answer:

Explanation:

The two charges are q and Q - q. Let the distance between them is r

Use the formula for coulomb's law for the force between the two charges

F = \frac{Kq_{1}q_{2}}{r^{2}}

So, the force between the charges q and Q - q is given by

F = \frac{K\left ( Q-q \right )q}}{r^{2}}

For maxima and minima, differentiate the force with respect to q.

\frac{dF}{dq} = \frac{k}{r^{2}}\times \left ( Q - 2q \right )

For maxima and minima, the value of dF/dq = 0

So, we get

q = Q /2

Now \frac{d^{2}F}{dq^{2}} = \frac{-2k}{r^{2}}

the double derivate is negative, so the force is maxima when q = Q / 2 .

6 0
4 years ago
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