A.Bohr
His model postulated the existence of energy levels or shells of electrons. Electrons could only be found in these specific energy levels; in other words, their energy was quantised, and couldn’t take just any value. Electrons could move between these energy levels but had to do so by either absorbing or emitting energy.
Since it was dropped, it should be the speed of gravity which is 9.8 meters/second
To solve this problem we must use the concepts related to the Law of Malus and the intensity of light. The intensity of a linearly polarized beam of light, which passes through a perfect analyzer and vertical optical axis is equivalent to:
Where,
indicates the intensity of the light before passing through the polarizer
is the resulting intensity
indicates the angle between the axis of the analyzer and the polarization axis of the incident light.
Since the light has the same intensity after the first polarizer we approach the second intensity directly so
Our values are given as :
Therefore replacing and re-arrange to find the angle we have
Therefore the angle of the second polarizer with respect to the first one is 57.1°
Answer:
the answer is D metal resting
Explanation:
I just think that because if you treasure can that's physical charge by dropping where you create a physical charge melting and Ice Cube might be 1 but I feel like metal resting is more likely
Answer:
U_total = 3.51 10⁻¹ J
Explanation:
The electic potential energy is
U = ∑ k qi qj / rij
Where k is the Coulomb constant 8.988 109 N m² / C², q are the electric charges and r is the distance between them
Let's apply this equation to our case
Total U = U₁₂ + U₁₃ + U₂₃
The distance between them is the length of the triangle L= 0.3 m, the charge are equal q = 1.40 10⁻⁶ C
U₁₂ = k q₂ / L
All energies are equal for this case, we substitute in the total potential energy
U_total = 3 (k q² / L)
U_total = 6 k q² / L
We calculate
U_total = 6 8,988 10⁹ (1.40 10⁻⁶)² / 0.3
U_total = 3.51 10⁻¹ J