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3 years ago

Just wondering, what do you guys think the 5th dimension is? I've always believed it to be light.

1 answer:

8 0

Answer: In the 5th dimension, they who claim to know, say that there is only one time, including the past and the future.

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A ball rolls over the edge of a platform with only a horizontal velocity. The height of the platform is 1.6 m and the horizontal

Sever21 [200]

Explanation:

the answer is in the above image

3 0

2 years ago

Three equal charge 1.8*10^-8 each are located at the corner of an equilateral triangle ABC side 10cm.calculate the electric pote

Arlecino [84]

Answer:

If all these three charges are positive with a magnitude of $1.8 \times 10^{-8}\; \rm C$ each, the electric potential at the midpoint of segment $\rm AB$ would be approximately $8.3 \times 10^{3}\; \rm V$ .

Explanation:

Convert the unit of the length of each side of this triangle to meters: $10\; \rm cm = 0.10\; \rm m$ .

Distance between the midpoint of $\rm AB$ and each of the three charges:

$d({\rm A}) = 0.050\; \rm m$ .
$d({\rm B}) = 0.050\; \rm m$ .
$d({\rm C}) = \sqrt{3} \times (0.050\; \rm m)$ .

Let $k$ denote Coulomb's constant ( $k \approx 8.99 \times 10^{9}\; \rm N \cdot m^{2} \cdot C^{-2}$ .)

Electric potential due to the charge at $\rm A$ : $\displaystyle \frac{k\, q}{d({\rm A})}$ .

Electric potential due to the charge at $\rm B$ : $\displaystyle \frac{k\, q}{d({\rm B})}$ .

Electric potential due to the charge at $\rm A$ : $\displaystyle \frac{k\, q}{d({\rm C})}$ .

While forces are vectors, electric potentials are scalars. When more than one electric fields are superposed over one another, the resultant electric potential at some point would be the scalar sum of the electric potential at that position due to each of these fields.

Hence, the electric field at the midpoint of $\rm AB$ due to all these three charges would be:

$\begin{aligned}& \frac{k\, q}{d({\rm A})} + \frac{k\, q}{d({\rm B})} + \frac{k\, q}{d({\rm C})} \\ &= k\, \left(\frac{q}{d({\rm A})} + \frac{q}{d({\rm B})} + \frac{q}{d({\rm C})}\right) \\ &\approx 8.99 \times 10^{9}\; \rm N \cdot m^{2} \cdot C^{-2} \\ & \quad \quad \times \left(\frac{1.8 \times 10^{-8} \; \rm C}{0.050\; \rm m} + \frac{1.8 \times 10^{-8} \; \rm C}{0.050\; \rm m} + \frac{1.8 \times 10^{-8} \; \rm C}{\sqrt{3} \times (0.050\; \rm m)}\right) \\ &\approx 8.3 \times 10^{3}\; \rm V\end{aligned}$ .

4 0

2 years ago

Why is a spectrum of colors produced when white light passes through a prism?

Mkey [24]

Explanation: White light is all colors of light in one, so when white light passes through a prism, the light gets refracted and breaks apart into all of the colors on the visible light spectrum.

4 0

2 years ago

If you were asked to describe metals and magnetism you could say?

Anettt [7]

Some metals having unpaired electrons contain a strong magnetic response, i.e, they can be magnetized by an external magnetic field.

5 0

2 years ago

Explain how evidence of energy transformation in fireworks supports the law of conservation of energy.

Varvara68 [4.7K]

Energy transformation in fireworks supports the law of conservation of energy because the total chemical energy packed into the fireworks before they ignite must be the same as the total remaining after it explodes... I hope this was the answer you were looking for.. I love your Yoongi pfp btw! :) </3

7 0

2 years ago