Answer:
Given
mᴀ = mʙ = mᴄ = 62 kg
Fᴀ = 480N
Fʙ = 240 N
Fᴄ = 600 N
Asked
aᴀ, aʙ, aᴄ = ?
Solution
Based on the question, we know that the mass of road A, road B and road C are same. And, the formula of acceleration is
so, we can calculate the acceleration of road A, road B and road C.
• for road A
aᴀ = 7,7419 m/s²
aᴀ = 7,75 m/s²
• for road B
aʙ = 3,8709 m/s²
aʙ = 3,87 m/s²
• for road C
aᴄ = 9,6774 m/s²
aᴄ = 9,68 m/s²
Explanation:
Answer:
A molecule of an element is composed of exactly two types of atoms.
Explanation:
Answer:
Value that the spring constant k = 12Mg / h
Explanation:
According to 2nd law of Newton:
upward force of the spring= F
The weight of the elevator W = mg
F = Mg = M(5g)
==> F =6Mg.
As the spring is compressed to its maximum distance ie s,the maximum upward acceleration comes just , Hence
F =ks = 6Mg
==> s = 6Mg/k
We have gravitational potential energy turning into elastic potential of the spring as the elevator starts at the top some distance h from the spring, and undergoes a total change in height equal to h + s, so:
Mg(h+s) = 1/2ks2
And plugging in our expression for s:
Mg(h+6Mg/k)= 1/2k(6Mg / k)2
gh + 6M2g2/k = 1/2k(36M2g2 /k2)
Mgh +6M2g2/k = 1/2k(36M2g2 /k2)
gh + 6Mg2/k = 18Mg2 / k
gh = 12Mg2 / k
h = 12Mg / k
k = 12Mg / h
Answer:
Yes, there is such a way.
Explanation:
If currents flow in the same direction in two or more long parallel wires, there will be an attractive force between the wires. If the current flows in different directions, there will be a repulsive force between the wires. In this case, these three parallel wires, can be be made to carry current in the same direction, creating an attractive force between all three wires.
Note that it is not possible to have at the least one of them carry current in the opposite direction and still have an attractive current between them.
