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yan [13]
3 years ago
5

Pleeease help meeeeee

Physics
1 answer:
VLD [36.1K]3 years ago
5 0
The average speed is 52km
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A car collides head on with a stationary sign. The collision brings the car to a stop, but the sign does not move.
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A.a sign that breaks loose from the ground when a force is applied to it

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3 years ago
A merry go round exerts a force of 1000 N on a rider on the
SVEN [57.7K]

Answer:

The radius of the circle made by the person on the merry go round is 74.55 meters

Explanation:

The given parameters are;

The force the merry go round exerts on the rider = 1000 N

The time it takes the merry go round to make one complete revolution = 15 seconds

The weight of the person = 750 N

The radius of the circle made by the person on the merry go round = r

We have;

F_c = \dfrac{m \cdot v^2}{r} = m \cdot \omega ^2 \cdot r

Where;

m = The mass of the person

v = The velocity of the person

F_c = The centrifugal force acting on the person = 1,000 N

r = The radius of the circle made by the person on the merry go round

ω = Angular velocity = 2·π/15 rad/s

We have;

The mass of the person = The weight/(The acceleration due to gravity, g)

∴ The mass of the person = 750/9.81 ≈ 76.45 kg

By substituting the calculated and known values into the equation for  the centripetal force, we have;

F_c = m × ω² × r

1000 = 76.45 × (2·π/15)² × r

r = 1000/(76.45 × (2·π/15)²) = 74.55 m

The radius of the circle made by the person on the merry go round = r = 74.55 m.

3 0
3 years ago
A ball rolled 10 meters in 2 seconds. Its velocity is m/s
dalvyx [7]

Answer:

velocity is 5m/s

Explanation:

data

d=10m

t=2sec

v=?

from

v=d/t

v=10m/2s

v=5m/s

8 0
3 years ago
Read 2 more answers
If a car is traveling on the highway at a constant velocity, the force that pushes the car forward must be A. equal to the weigh
Gala2k [10]

the correct answer is c

4 0
4 years ago
A man of mass 81 kg escapes from a burning building by jumping from a window situated 32 m above a catching net. The acceleratio
Dafna1 [17]

Answer:

The speed of man before he hits the ground is <u>23.35 m/s</u>

Explanation:

We know that:

Weight of Man - Force of Friction = Unbalanced Force

but, from Newton's 2nd Law of Motion:

unbalanced force = ma

Therefore,

W - F = ma

a = (W - F)/m

a = (mg - F)/m

where,

m = 81 kg

g = 9.8 m/s²

F = 103 N

a = [(81 kg)(9.8 m/s²) - 103 N]/81 kg

a = 8.52 m/s²

using 3rd equation of motion:

Vf² - Vi² = 2ah

here,

Vi = initial velocity = 0 m/s

Vf = Final Velocity before he hits ground = ?

Vf² - 0² = 2(8.52 m/s²)(32 m)

Vf = √545.28 m²/s²

<u>Vf = 23.35 m/s</u>

4 0
3 years ago
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