Consider a cup on a dinning table half filled with water.

What are typical uses of Mainframe computer?

madam [21]

a computer used primarily by large organizations for critical applications like bulk data processing for tasks such as censuses, industry and consumer statistics, enterprise resource planning, and large-scale transaction processing

7 0

3 years ago

Given that the company "Slate Rock and Gravel" has business locations in Granitetown and Bedrock, suppose that the company has b

kotegsom [21]

Answer:

Check the explanation

Explanation:

As Granitetown requires 5000 IP address and the starting IP address is 192.172.0.0 , we have to perform subnetting using number of hosts required

Number of IP address required by Granitetown=4000

Number of hosts bits =

2n -2= 5000

n=13 (approximately)

Number of hosts bits are 13 therefore subnet prefix =(32-13)=19

We have used 32 because IP address is of 32-bit

Subnet mask corresponding to /19 = 255.255.224.0

Starting IP address (given)= 192.172.0.0

Now to calculate last IP address of the subnet, OR operation will be performed between First IP address of the subnet and !Netmask

First IP address of subnet ( in binary) =

11000000.10101100.00000000.00000000

OR

00000000.00000000.00011111.11111111 (!Netmask)

11000000.10101100.000 11111.11111111 (result)

Converting result into decimal gives IP address 192.172.31.255 which will be the broadcast IP address of the subnet therefore

Last usable IP address = 192.172.31.254

Now, bedrock requires 2000 IP address

Therefore number of host bits are =

2n -2 =2000

n=10 (approximately)

Number of hosts bits required are 10

Therefore Netmask prefix = (32 -10) =22

Now, using the next subnet for bedrock therefore the first IP address of subnet will be 192.172.32.0

Now, similarly calculating last IP address of subnet

First IP address in binary =

11000000.10101100.00100000.00000000

OR

00000000.00000000.00000011.11111111 (!Netmask)

11000000.10101100.00100011.11111111 (result)

Now, result in decimal = 192.172.35.255

Therefore ,

Broadcast address of subnet =192.172.35.255

Last usable IP address =192.172.35.254

8 0

4 years ago

Design a 8th order wideband band-pass Butterworth filter with a lower cutoff frequency of 45 Hz, an upper cutoff frequency of 17

Lunna [17]

Explanation:

71hz 45+17+9

5 0

2 years ago

What's the best way to find the load capacity of a crane? Select the best option. Call the manufacturer Ask co-workers Look at t

Orlov [11]

Answer: You need to lift a load of 15 tons (30,000 pounds) a distance of 25 feet. The distance is measured from the center pin of the crane to the center of the load. Once you determine the distance, look on that line for the largest capacity; that will indicate how many feet of boom must be extended

Explanation:

5 0

3 years ago

Based on experimental observations, the acceleration of a particle is defined by the relation a = –(0.1 + sin x/b), where a and

Allisa [31]

Answer:

a) v = +/- 0.515 m/s

b) x = -0.098164 m

c) v = +/- 1.005 m/s

Explanation:

Given:

The relationship for the acceleration is given as follows:

a = - (0.1 + sin(x/b))

Where, b = 0.98

- IVP is v = 1 m/s @ x = 0

Find:

(a) the velocity of the particle when x = -1 m

(b) the position where the velocity is maximum

(c) the maximum velocity.

Solution:

- We will compute the velocity by integrating a by dt.

a = v*dv / dx = - (0.1 + sin(x/0.98))

- Separate variables:

v*dv = - (0.1 + sin(x/0.98)) . dx

-Integrate from v = 1 m/s to v and @ x = 0 to x:

0.5*(v^2) = - (0.1*x - 0.98*cos(x/0.8)) - 0.98 + 0.5

0.5*v^2 = 0.98*cos(x/0.98) - 0.1*x - 0.48

- Evaluate at, x = -1

0.5*v^2 = 0.98 cos(-1/0.98) + 0.1 -0.48

v = sqrt (0.2651155)

v = +/- 0.515 m/s

- v = v_max when a = 0. Set the given expression to zero and solve for x:

-0.1 = sin(x/0.98)

x = -0.98*0.1002

x = -0.098164 m

- Hence now evaluate velocity through the derived expression:

v^2 = 1.96 cos(-0.098164/0.98) -0.96 -0.2*-0.098164

v = sqrt (1.0098)

v = +/- 1.005 m/s

4 0

3 years ago