Answer:
0.144M
Explanation:
First, let us write a balanced equation for the reaction. This is illustrated below:
HNO3 + KOH —> KNO3 + H20
From the equation,
nA = 1
nB = 1
From the question given, we obtained the following:
Ma =?
Va = 30.00mL
Mb = 0.1000M
Vb = 43.13 mL
MaVa / MbVb = nA/nB
Ma x 30 / 0.1 x 43.13 = 1
Cross multiply to express in linear form
Ma x 30 = 0.1 x 43.13
Divide both side by 30
Ma = (0.1 x 43.13) /30 = 0.144M
The molarity of the nitric acid is 0.144M
Answer is: 0.330 ppm
Hope this helps
Answer: The number of moles of 
produced are, 0.287 moles.
Explanation : Given,
Mass of 
= 14.9 g
Molar mass of = 32 g/mol
First we have to calculate the moles of
Now we have to calculate the moles of
The balanced chemical equation is:
From the reaction, we conclude that
As, 13 mole of react to give 8 moles of
So, 0.466 mole of react to give 
mole of
Therefore, the number of moles of produced are, 0.287 moles.
Answer is: H+ will increase and OH− will decrease.
pH = 11.4.
pH = -log[H+].
[H+] = 10∧(-pH).
[H+] = 10∧(-11.4).
[H+] = 4·10⁻¹² mol/L.
[H+] · [OH-] = 1·10⁻¹⁴ mol²/dm⁶.
[OH-] = 0.0025 mol/L.
pH value (potential of hydrogen - [H+]) is a logarithmic scale that specify the acidity or basicity of an aqueous solution.
When pH is greater than seven, aqueous solution is basic, below seven is acidic and when pH is equal seven, solution is neutral.
Answer:
Species M. furo and F. catus
Explanation:
When you look at their family name, both species have -<em>lidae </em>at the end, indicating that they are more closely related.
