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3 years ago

14

Within the rock cycle, a metamorphic rock could become an igneous rock by going through which steps and in what order?

2 answers:

Yuki888 [10]3 years ago

5 0

Hello,

Question- Within the rock cycle, a metamorphic rock could become an igneous rock by going through which steps and in what order?

A. melting, cooling, crystallization

B. crystallization, melting, cooling

C. burial, compaction, cementation

D. weathering, transportation, burial

Answer- Your answer is A. Melting, cooling, crystallization.

Why- Any rock can become any rock igneous metamorphic or even condemnatory just by heating up but when it melts it becomes lava and the rock cycle starts all over again. See all it has to do to become a new phase of rock is two steps melt and cool and boom its a new phase of rock.

Important- If my answer was enough to help uou please mark me as Brainliest, Leave a thanks, and Rate my answer 5 stars thank you and have the best day ever!

swat323 years ago

3 0

Answer:

a is the right anwser it just makes sence

Explanation:

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what is the balanced equation for when an aqueous solution of hydrochloric acid reacts with sodium metal, aqueous sodium chlorin

FinnZ [79.3K]

Answer:

2Na(s) + 2HCl(aq) —> 2NaCl(aq) + H2(g)

Explanation:

Na(s) + HCl(aq) —> NaCl(aq) + H2(g)

Writing an ionic equation will actually help us to understand the equation and also to balance it. This is illustrated below:

Na + H+Cl-

Na is higher than H in the activity series and as such, it will displaces H from the solution and form NaCl with H2 liberated as shown below

Na + H+Cl- —> Na+Cl- + H2

Now, put 2 in front of Na, H+Cl- and Na+Cl- to balance the equation as shown below:

2Na + 2H+Cl- —> 2Na+Cl- + H2

Now we can write the elemental equation as follow:

2Na(s) + 2HCl(aq) —> 2NaCl(aq) + H2(g)

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3 years ago

Hey, please could someone answer this?

pav-90 [236]

Carbon dioxide is the other product created.

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3 years ago

What is the volume of stank of nitrogen that contains 17 moles of nitrogen at 34 C under 12,000Pa?

Otrada [13]

Answer:

3626.76dm³

Explanation:

Given parameters:

Number of moles of Nitrogen in tank = 17moles

Temperature of the gas = 34°C

Pressure on the gas = 12000Pa

Unkown:

Volume of the tank, V =?

Converting the parameters to workable units:

We take the temperature from °C to Kelvin

K = 273 + °C = 273 + 34 = 307k

Taking the pressure in Pa to atm:

101325Pa = 1atm

12000Pa = 0.118atm

Solution:

To solve this problem, we employ the use of the ideal gas equation. The ideal gas law combines three gas laws which are the Boyle's law, Charles's law and the Avogadro's law.

It is expressed as PV = nRT

The unknown is the Volume and we make it the subject of the formula

V = $\frac{nRT}{P}$

Where R is called the gas constant and it is given as 0.082atmdm³mol⁻¹K⁻¹

Therefore V = $\frac{17 x 0.082 x 307 }{0.118}$ = 3626.76dm³

3 0

3 years ago

Read 2 more answers

Sulfur dioxide, SO 2 ( g ) , can react with oxygen to produce sulfur trioxide, SO 3 ( g ) , by the reaction 2 SO 2 ( g ) + O 2 (

aleksley [76]

<u>Answer:</u> The amount of heat produced by the reaction is -21.36 kJ

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles.

The equation used to calculate enthalpy change is of a reaction is:

$\Delta H^o_{rxn}=\sum [n\times \Delta H_f_{(product)}]-\sum [n\times \Delta H_f_{(reactant)}]$

For the given chemical reaction:

$2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)$

The equation for the enthalpy change of the above reaction is:

$\Delta H_{rxn}=[(2\times \Delta H_f_{(SO_3(g))})]-[(2\times \Delta H_f_{(SO_2(g))})+(1\times \Delta H_f_{(O_2(g))})]$

We are given:

$\Delta H_f_{(SO_2(g))}=-296.8kJ/mol\\\Delta H_f_{(SO_3(g))}=-395.7kJ/mol\\\Delta H_f_{(O_2(g))}=0kJ/mol$

Putting values in above equation, we get:

$\Delta H_{rxn}=[(2\times (-395.7))]-[(2\times (-296.8))+(1\times (0))]\\\\\Delta H_{rxn}=-197.8kJ/mol$

To calculate the number of moles, we use ideal gas equation, which is:

$PV=nRT$

where,

P = pressure of the gas = 1.00 bar

V = Volume of the gas = 2.67 L

n = number of moles of gas = ?

R = Gas constant = $0.0831\text{ L. bar }mol^{-1}K^{-1}$

T = temperature of the mixture = $25^oC=[25+273]K=298K$

Putting values in above equation, we get:

$1.00bar\times 2.67L=n\times 0.0831\text{ L. bar }mol^{-1}K^{-1}\times 298K\\\\n=\frac{1\times 2.67}{0.0831\times 298}=0.108mol$

To calculate the heat released of the reaction, we use the equation:

$\Delta H_{rxn}=\frac{q}{n}$

where,

q = amount of heat released = ?

n = number of moles = 0.108 moles

$\Delta H_{rxn}$ = enthalpy change of the reaction = -197.8 kJ/mol

Putting values in above equation, we get:

$-197.8kJ/mol=\frac{q}{0.108mol}\\\\q=(-197.8kJ/mol\times 0.108mol)=-21.36kJ$

Hence, the amount of heat produced by the reaction is -21.36 kJ

3 0

3 years ago

Which of the following is NOT an example of proxy data?

Tomtit [17]

Answer:

itz e

Explanation:

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3 years ago