Question

What is the osmotic pressure, in atm, of a 0.287 M solution of MgCl2 at

Answer 1

Answer:

Π = 21.9 atm

Explanation:

The equation used to find osmotic pressure is:

Π = iMRT

In this formula,

   >> Π = osmotic pressure (atm)

   >> i = van't Hoff factor

   >> M = molarity (M)

   >> R = constant (0.0821 atm*L/mol*K)

   >> T = temperature (K)

Remember, van't Hoff factor is the amount of ions the species (MgCl₂) dissociates into while in solution. MgCl₂ dissociates into 3 ions. These ions are Mg²⁺ and 2 Cl⁻.

The temperature needs to be in Kelvin....

37.0 °C + 273.15 = 310.15 K

You now know the value of all the variables.

Π = iMRT

Π = (3)(0.287 M)(0.0821 atm*L/mol*K)(310.15 K)

Π = 21.9 atm