Answer:
2.067 L ≅ 2.07 L.
Explanation:
- The balanced equation for the mentioned reaction is:
<em>CS₂(g) + 3O₂(g) → CO₂(g) + 2SO₂(g),</em>
It is clear that 1.0 mole of CS₂ react with 3.0 mole of O₂ to produce 1.0 mole of CO₂ and 2.0 moles of SO₂.
- At STP, 3.6 L of H₂ reacts with (?? L) of oxygen gas:
It is known that at STP: every 1.0 mol of any gas occupies 22.4 L.
<u><em>using cross multiplication:</em></u>
1.0 mol of O₂ represents → 22.4 L.
??? mol of O₂ represents → 3.1 L.
∴ 3.1 L of O₂ represents = (1.0 mol)(3.1 L)/(22.4 L) = 0.1384 mol.
- To find the no. of moles of SO₂ produced from 3.1 liters (0.1384 mol) of hydrogen:
<u><em>Using cross multiplication:</em></u>
3.0 mol of O₂ produce → 2.0 mol of SO₂, from stichiometry.
0.1384 mol of O₂ produce → ??? mol of SO₂.
∴ The no. of moles of SO₂ = (2.0 mol)(0.1384 mol)/(3.0 mol) = 0.09227 mol.
- Again, using cross multiplication:
1.0 mol of SO₂ represents → 22.4 L, at STP.
0.09227 mol of SO₂ represents → ??? L.
∴ The no. of liters of SO₂ will be produced = (0.09227 mol)(22.4 L)/(1.0 mol) = 2.067 L ≅ 2.07 L.
Answer:
The correct answer is 17 meq/g
Explanation:
Ion exchange capacity (IEC) express the total of active sites of a resin in which ions are attached because the greater molecular weight.
The exchange Reaction can be represented as
R-H
The IEC value (in meq/g) is determinated by using the next equation:
IEC=[(mL of NaOH)*(M of NaOH)]/mass of resin
IEC [(17 mL)*(0.5 M)/0.5]= 17 meq/g
Water i think because it’s a pure substance
Answer: A reaction which occurs when equivalent quantities of H" (or 
) and OH" are mixed is a neutralization reaction.
Explanation:
When acid and base chemically combine together to form sat and water then it is know as neutralization reaction.
An acidic substance gives hydrogen ions 
on dissociation and a basic substance gives hydroxide ions 
on dissociation.
For example, 
is a neutralization reaction where an acid and base are mixed together to form water.
No salt is formed as because here the reactants are not present as compounds.
In a hydrolysis reaction, water molecule(s) is added to the reactant molecules.
For example, 
Oxidation is the process of addition of oxygen to a molecule and removal of hydrogen.
Reduction is the process of addition of hydrogen in a compound and the removal of oxygen atom.
Therefore, we can conclude that reaction which occurs when equivalent quantities of H" (or ) and OH" are mixed is a neutralization reaction.
Answer:
25cm³ = 0.025L of H2So4
Molarity of H2SO4 = 1moldm-³
Recall ... 1dm-³ = 1L
So the Molarity can also be 1mol/L
Mole = Molarity x volume in L
Mole of H2SO4 = 1mol/L x 0.025L
=0.025Moles of Sulphuric acid reacted.
From the equation of reaction
1mole of H2SO4 reacts to produce 1mole of Copper sulphate crystal
Since their Mole ratio is 1:1
It means that Since 0.025mole of H2SO4 reacted.... 0.025mole of CuSO4.5H2O would be produced
Nice.. OK
So we know the moles of CuSO4.5H2O produced
We can get the Mass
Recall
From
Mole=Mass/Molar Mass
Mass = Mole x Molar Mass
Molar Mass of CuSO4.5H2O = 64 + 32 + 16x4+ 5(2+16)
Mm= 250g/mol
Mass = 0.025mol x 250g/mol
= 6.25g of CuSO4.5H2O crystals Would be PRODUCED.
