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77julia77 [94]
2 years ago
9

The circle below is center Ed at O. Decide which length,if any, is definitely the same as the length. a) AD. b) BC. Justify your

answers

Mathematics
1 answer:
Mars2501 [29]2 years ago
5 0

Answer:

Point O is the center of the circle.

<u>Part (a)</u>

\overline{A\:\!F} is a chord.

\overline{OD} is a segment of the radius and is perpendicular to  \overline{A\:\!F}

If a radius is perpendicular to a chord, it bisects the chord (divides the chord into two equal parts).

Therefore, \overline{AD}=\overline{DF}

<u>Part (b)</u>

If \overline{BE} was extended past point E to touch the circumference it would be a chord.

As \overline{OC} is perpendicular to \overline{BE},  it would bisect the chord, but as \overline{BE} is only a portion of a chord, \overline{OC} <u>does not</u> bisect \overline{BE}.

Therefore, there is no length equal to \overline{BC}.

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