2. 3 3/4 3. 1 2/4 4. 3 days
Answer:
-390 mph
Step-by-step explanation:
Let a and b represent, respectively, the distances of A and B from the airport. The distance d between the planes is then given by the Pythagorean theorem as ...
d² = a² + b²
Differentiating with respect to time, we have ...
2d·d' = 2a·a' +2b·b'
Solving for d', we get ...
d' = (a/d)a' +(b/d)b'
The value of d at the time of interest is ...
d = √(a² +b²) = √(30² +40²) = √2500 = 50
Then the rate of change of separation is ...
d' = (30/50)(-250 mph) +(40/50)(-300 mph) = (-150 -240) mph
d' = -390 mph
The distance between planes is decreasing at 390 miles per hour.
Answer:
0.25 minutes
Step-by-step explanation:
It will take 1/12 the time for the duck to fly 1/12 the distance. Therefore, it will take 3 * 1/12 minutes which is 0.25 (1/4 in fraction form).
Hope this helps :)
Answer:
24 is the answer
Step-by-step explanation:
answer is 24 for base
F(x)=-2e^x
x=3
f(3)=-2e^3
pemdas so exponents first
e^3
e=2.718281828454590
cube that
20.0855
now we have
-2 times 20.0855=-40.1711
answer should be -40.1711
(I see what you did wrong, if -6=-2 times e^3, divide -2, 3=e^3, maybe you just put -2 times 3 by mistake)