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ra1l [238]
2 years ago
14

What is the number of molecules in CaCo3

Chemistry
1 answer:
Damm [24]2 years ago
4 0

Answer:

Solution — Molar mass (Molecular mass in gram) of CaCO3 = 40+12+3×16 = 100 g No. of moles of CaCO3 = No. of molecules/Avogadro constant = 6.022 × 1023/ 6.022 × 1023 = 1 mole Mass of CaCO3 = No. of moles × molar mass = 1 × 100 g = 100 g.

Explanation:

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How many atoms are in 159 g of calcium?<br><br> 159 g =
AnnZ [28]

Answer:

Answer : The number of atoms present in 159 g of calcium are

Explanation :

First we have to calculate the moles of calcium.

Molar mass of calcium = 40 g/mole

Now we have to calculate the number of atoms of calcium.

As, 1 mole of calcium contains  number of atoms of calcium

So, 3.975 mole of calcium contains  number of atoms of calcium

Therefore, the number of atoms present in 159 g of calcium are

Explanation:

4 0
3 years ago
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A wheelbarrow can be used to help lift a load, such as a pile of dirt, and then push the load across a distance.
mrs_skeptik [129]

Answer: it consists of two simple machines: a lever and a wheel and axle. Effort is applied to the lever by picking up the handles of the wheelbarrow.

Explanation:

4 0
3 years ago
Which clue can be used to identify a chemical reaction as a decomposition reaction?
inn [45]

Answer:

plzz mark brainliast:

Explanation:

clue: The reaction has a single reactant.

8 0
3 years ago
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What does rxns standfor?
VLD [36.1K]

rxns is an abbreviation for reactions

7 0
3 years ago
The half life of iodine-125 is 60 days. What was the initial amount of iodine-125 if you have 4.5 grams after 360 days?
ValentinkaMS [17]

Answer:

288 grams

Explanation:

The amount of any radiative substance left after some time is calculated by

amount left = x/2^n

where x is the initial amount of substance

n is the number of half lives

one half live is the time in which amount of substance reduce to half of its initial value.

------------------------------------------------------

amount left = 4.5 grams

half life of  iodine-125 = 60 days

total time in which substance reduced to 4.5 grams  = 360 days

thus,

number of half life in 60 days = 360/60 = 6

thus, there are period of 6 half lives

in each half life the amount of substance reduces to its previous half

let the initial amount be x grams

using the formula

amount left = x/2^n

4.5 = x/2^6 \\ 4.5 = x/64\\x = 4.5*64 = 288

Thus, 288 grams was the initial amount of iodine-125

6 0
3 years ago
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