An aqueous solution of an arrhenius acid reacts with an aqueous solution of an arrhenius base to produce water and salt.
<h3>What is a Salt?</h3>
This is a compound which is formed as a result of a neutralization reaction between acid and base.
Arrhenius acid reacts with an aqueous solution of an arrhenius base to produce water and salt due to increased concentration of H+ and OH- respectively.
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Answer:
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Answer:
91383 J
Explanation:
The equation of the reaction can be represented as:
------>![NO_{(g)}](https://tex.z-dn.net/?f=NO_%7B%28g%29%7D)
Given that:
The standard enthalpy of formation of NO(g) is 91.3 kJ⋅mol−1 at 298.15 K.
The equation below shown the reaction between the enthalpy of reaction at a particular temperature to another.
= ![\delta H^0__{R,T_1} } + \int\limits^{T_2}_{T_1} {\delta C_p(T')} \, dT'](https://tex.z-dn.net/?f=%5Cdelta%20H%5E0__%7BR%2CT_1%7D%20%7D%20%2B%20%5Cint%5Climits%5E%7BT_2%7D_%7BT_1%7D%20%7B%5Cdelta%20C_p%28T%27%29%7D%20%5C%2C%20dT%27)
where:
= enthalpy of reaction
= the difference in the heat capacities of the products and the reactants.
∴
=
![\int\limits^{435}_{298.15} {\delta C_p(T')} \, dT'](https://tex.z-dn.net/?f=%5Cint%5Climits%5E%7B435%7D_%7B298.15%7D%20%7B%5Cdelta%20C_p%28T%27%29%7D%20%5C%2C%20dT%27)
= ![1(91300 J.mol^{-1} ) +\int\limits^{435}_{298.15} [{(29.86)-\frac{1}{2}(29.38)-\frac{1}{2}29.13}]J.K^{-1}.mol^{-1} \, dT'](https://tex.z-dn.net/?f=1%2891300%20J.mol%5E%7B-1%7D%20%29%20%2B%5Cint%5Climits%5E%7B435%7D_%7B298.15%7D%20%5B%7B%2829.86%29-%5Cfrac%7B1%7D%7B2%7D%2829.38%29-%5Cfrac%7B1%7D%7B2%7D29.13%7D%5DJ.K%5E%7B-1%7D.mol%5E%7B-1%7D%20%5C%2C%20dT%27)
= 91300 J + (0.605 J.K⁻¹)(435-298.15)K
= 91382.79 J
≅ 91383 J
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