Answer:
ΔG = - 590.20 kJ/mol
Explanation:
The formula for calculating Gibb's Free Energy can be written as:
ΔG = ΔH - TΔS
Given That:
ΔH = -720.5 kJ/mol
T = 221.0°C = (221.0 + 273.15) = 494.15 K
ΔS° = -263.7 J/K
So; ΔS° = -0.2637 kJ/K if being converted from joule to Kilo-joule
Since we are all set, let replace our given data in the above equation:
ΔG = (-720.5 kJ/mol) - (494.15 K) ( - 0.2637 kJ/K)
ΔG = (-720.5 kJ/mol) - (- 130.30755)
ΔG = -720.5 kJ/mol + 130.30755
ΔG = -590.192645 kJ/mol
ΔG = - 590.20 kJ/mol
Thus, The value of ΔG° at 221.0°C for the formation of phosphorous trichloride from its constituent elements, P2(g) + 3Cl2(g) → 2PCl3(g) is <u>-590.20</u> kJ/mol.
Answer:
Mass of HCl = 73 g
Explanation:
Given data:
Mass of hydrogen = 2 g
Mass of HCl = ?
Solution:
First of all we will write the balance chemical equation:
H₂ + Cl₂ → 2HCl
Number of moles of hydrogen = 2 g/ 2g/mol
Number of moles of hydrogen = 1 mol
Form balanced chemical equation compare the moles hydrogen with HCl.
H₂ : HCl
1 : 2
Mass of HCl:
Mass of HCl = number of moles × molar mass
Mass of HCl = 2 mol × 36.5 g/mol
Mass of HCl = 73 g
Compressed is the answer!
I hope this helps. :)
Answer:
Number of moles of HCl = 0.17 mol
Explanation:
Given data:
Volume of solution = 347 mL
Molarity of solution = 0.48 M
Number of moles of HCl present = ?
Solution:
Formula:
Molarity = number of moles of HCl / volume in L
Volume in L:
347 mL× 1L / 1000 mL
0.347 L
by putting values in formula:
0.48 mol/L = number of moles / 0.347 L
Number of moles = 0.48 mol/L × 0.347 L
Number of moles = 0.17 mol
Answer:
ending point
Step by step explanation:
