What does rxns standfor?

Mario studied how far room temperature water would spurt out of a platic milk carton when 3mm holes were punched at different he

aliina [53]

Answer:

C. Different heights of holes in the container

Explanation:

The independent variable is the variable that changes. So the independent variable is C because the heights of the holes change.

8 0

3 years ago

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Finish the following word equation. calcium + nitric acid →

Dafna1 [17]

HNO3 + Ca —-> H2O + N20 + Ca(NO3)2

4 0

2 years ago

What is a common use of bases?

Fittoniya [83]

A common use of bases is to reduce indigestion. Hence, option D is correct.

A base is a substance that can neutralize the acid by reacting with hydrogen ions.

Bases are substances whose solutions have a pH value of more than 7. Bases are bitter in taste.

Whereas acids are the substances whose solutions have a pH value of less than 7. Acids are sour in taste.

When an excess of acid is formed in the human stomach then an antacid tablet which is basically a base is consumed that helps in reducing indigestion.

Therefore, we can conclude that the common use of bases is to reduce indigestion.

Learn more about the base here:

brainly.com/question/1432645

#SPJ1

3 0

1 year ago

At equilibrium, the concentrations of the products and reactants for the reaction, H2 (g) + I2 (g)  2 HI (g), are [H2] = 0.106

lana [24]

Answer:

The new equilibrium concentration of HI: [HI] = 3.589 M

Explanation:

Given: Initial concentrations at original equilibrium- [H₂] = 0.106 M; [I₂] = 0.022 M; [HI] = 1.29 M

Final concentrations at new equilibrium- [H₂] = 0.95 M; [I₂] = 0.019 M; [HI] = ? M

Given chemical reaction: H₂(g) + I₂(g) → 2 HI(g)

The equilibrium constant ( $K_{c}$ ) for the given chemical reaction, is given by the equation:

$K_{c} = \frac {[HI]^{2}}{[H_{2}]\: [I_{2}]}$

At the original equilibrium state:

$K_{c} = \frac {(1.29\: M)^{2}}{(0.106\: M) \times (0.022\: M)}$

$K_{c} = \frac {1.6641}{0.002332} = 713.59$

Therefore, at the new equilibrium state:

$K_{c} = \frac {[HI]^{2}}{(0.95\: M) \times (0.019\: M)}$

$\Rightarrow K_{c} = 713.59 = \frac {[HI]^{2}}{0.01805}$

$\Rightarrow [HI]^{2} = 713.59 \times 0.01805 = 12.88$

$\Rightarrow [HI] = \sqrt {12.88} = 3.589 M$

Therefore, the new equilibrium concentration of HI: [HI] = 3.589 M

6 0

2 years ago

Why is cyanide lethal? What dose it do once inside the body?

OLga [1]

In large doses it stops cells using oxygen causing these cells to die. So in a small amount it would not kill you. So lets say cyanide is inside the body it would kill off all the cells and your body would not be able to function causing death

3 0

2 years ago

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