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DerKrebs [107]
2 years ago
10

A minivan starts from rest on the road whose constant radius of curvature is 40 meters and whose bank angel is 10 degrees. the m

otion occurred in a horizontal plane. If the constant forward acceleration of the minivan is 1.8 m/s², determine the magnitude a of it's total acceleration 5 second after starting.
Engineering
1 answer:
zimovet [89]2 years ago
8 0

Based on the calculations, the magnitude (a) of it's total acceleration is equal to 2.71 m/s².

<u>Given the following data:</u>

  • Angle of inclination = 10°.
  • Radius of curvature, r = 40 meters.
  • Acceleration of the minivan, A = 1.8 m/s².
  • Initial velocity, u = 0 m/s (since it's starting from rest).
  • Time, t = 5 seconds.

<h3>How to determine the magnitude (a) of it's total acceleration?</h3>

First of all, we would determine the final velocity of the minivan by applying the first equation of motion as follows:

V = u + at

V = 0 + 1.8 × 5

V = 9 m/s.

Next, we would calculate the centripetal acceleration of this minivan:

Ac = V²/r

Ac = 9²/40

Ac = 2.025 m/s².

Now, we can determine the magnitude (a) of it's total acceleration:

a = √(Ac² + A²)

a = √(2.025² + 1.8²)

a = 2.71 m/s².

Read more on acceleration here: brainly.com/question/24728358

#SPJ1

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Answer:

Re=100,000⇒Q=275.25 \frac{W}{m^2}

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Explanation:

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<u> Take Re=500,000:</u>

So this is case of turbulent flow

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Nu=0.037\times 500,000^{\frac{4}{5}}\times 0.71^{\frac{1}{3}}

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Nu=0.037\times 1,000,000^{\frac{4}{5}}\times 0.71^{\frac{1}{3}}

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                             =19.87(179-25)

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