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jeka94
3 years ago
13

The viscosity of the water was 2.3×10^−5lb⋅⋅s/ft^2 and the water density was 1.94 slugs/ft^3. Estimate the drag on an 88-ft diam

eter balloon moving in air at a velocity of 3 ft/s. Assume the air to have a viscosity of 3.7×10^−7lb⋅⋅s/ft^2 and a density of 2.38×10^−3 slugs/ft^3. Also perform a dimensional analysis.

Engineering
1 answer:
Lina20 [59]3 years ago
6 0

Answer:

hello your question is incomplete attached below is the complete question

answer : Drag force = 1.3 Ib

Explanation:

we have to represent the dimensions of the drag force in terms of FLT

i.e : D = f( <em>d,v,p,u </em>) represented in terms of FLT

D = F , V = LT^-1,  d = L, p = FL^-4 T^2

u = FL^-2 T,  Number of independent terms = 5

attached below is the detailed solution

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Vilka [71]

Answer:

The following query is used to display TripName. Reservationld, FirstName. LastName and TotalCost of trip by adding the trip price plus other fees and multiplying the result by the number of persons which have number of persons >4.

Query:

SELECT ReservationlD, Trip.TripName. Customer.LastName. Customer.FirstName. (TripPrice+OtherFees) 'NumPersons as TotalCost FROM Reservation, Trip, Customer WHERE NumPersons>4 AND Reservation.TriplD=Trip.TriplD AND

Customer. CustomerNum=Reservation.CustomerNum:

Explanation:

  • Select clause is used to retrieve data from specified database table or relation and returns the data in the form of table.
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3 years ago
) In a disk test performed on a specimen 32-mm in diameter and 7 mm thick, the specimen fractures at a stress of 680 MPa. What w
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Answer:

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Explanation:

6 0
2 years ago
500 flights land each day at San Jose’s airport. Assume that each flight has a 5% chance of being late, independently of whether
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Answer:

a.0.0199

b.0.1765

c.0.0785

d.0.1268

e.Yes

Explanation:

It is given that   X follows a  Binomial distribution with (n= 500, p = 0.05)

The  probabilities  are computed using the EXCEL .

a) The required probability here is:

P(X less of equal to  15)

= binom.dist(15,500,0.05,TRUE)

=0.0199

Therefore the probability is 0.0199 .

b) The required probability here is:

P(X greater or equal to 30) = 1 - P(X less or equal to  29)  

=1 - binom.dist(29,500,0.05,TRUE)

=0.1765

Therefore the probability is 0.1765

c) P(X = 26 )

= binom.dist(26,500,0.05,FALSE)  

=0.0785

Therefore the probability is 0.0785

d) The required probability here is computed as:

P(10 less or equal to X less or equal to 20 ) = P(X less or equal to 19) - P(X less or equal to 10)

= binom.dist(19,500,0.05,TRUE) - binom.dist(10,500,0.05,TRUE)

=0.1268

Therefore the probability 0.1268

e) Yes . Therefore the probability because that is the assumption used to apply binomial distribution .

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The answer is A. Immediately inform her colleague
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Answer:

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