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jeka94
4 years ago
13

The viscosity of the water was 2.3×10^−5lb⋅⋅s/ft^2 and the water density was 1.94 slugs/ft^3. Estimate the drag on an 88-ft diam

eter balloon moving in air at a velocity of 3 ft/s. Assume the air to have a viscosity of 3.7×10^−7lb⋅⋅s/ft^2 and a density of 2.38×10^−3 slugs/ft^3. Also perform a dimensional analysis.

Engineering
1 answer:
Lina20 [59]4 years ago
6 0

Answer:

hello your question is incomplete attached below is the complete question

answer : Drag force = 1.3 Ib

Explanation:

we have to represent the dimensions of the drag force in terms of FLT

i.e : D = f( <em>d,v,p,u </em>) represented in terms of FLT

D = F , V = LT^-1,  d = L, p = FL^-4 T^2

u = FL^-2 T,  Number of independent terms = 5

attached below is the detailed solution

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Complete Question

The complete question is shown on the first uploaded image

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The probability is 0.958

Explanation:

The explanation is shown on the second and third uploaded image

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35

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Identify one of the advantages of 3d modeling?
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Answer:

Hello Adam here! (UWU)

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6 0
3 years ago
Consider the diffusion of water vapor through a polypropylene (PP) sheet 1 mm thick. The pressures of H2O at the two faces are 3
Neko [114]

Answer:

\boxed{0.000000266 \frac {cm^{3}.STP}{cm^{2}.s}}

Explanation:

Diffusion flux of a gas, J is given by

J=P_m\frac {\triangle P}{\triangle x} where P_m is permeability coefficient, \triangle P is pressure difference and x is thickness of membrane.

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At 298 K, the permeability coefficient of water vapour through polypropylene sheet is 38\times 10^{-13}(cm^{3}. STP)(cm)/(cm^{2}.s.Pa)

Since the thickness of sheet is given as 1mm= 0.1 cm then

J=38\times 10^{-13}(cm^{3}. STP)(cm)/(cm^{2}.s.Pa)\times \frac {7000 pa}{0.1cm}=0.000000266 \frac {cm^{3}.STP}{cm^{2}.s}

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