Answer: 1.137*10^7 Btu/h.
Explanation:
Given data:
Efficiency of the plant = 4.5percent
Net power output of the plant = 150kw
Solution:
The required collection rate
QH = W/n
= 150/0.045 * 0.94782/ 1 /60 */60 Btu/h.
= 3333.333 *3412.152Btu/h.
= 11373840 Btu/h
= 1.137*10^7 Btu/h.
 
        
             
        
        
        
Answer:https://global.oup.com/us/companion.websites/9780199385423/student/ch6/mcq/     just go here
Explanation:
 
        
             
        
        
        
I really don’t know good luck
        
             
        
        
        
Answer:
Coiled tubing is often used to carry out operations similar to wire lining.