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USPshnik [31]
3 years ago
15

In which forms do MOST of the Sun's energy reach Earth's surface?

Engineering
1 answer:
natta225 [31]3 years ago
4 0

Answer:

I believe the answer is B, visible and infrared light.

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A closed, 0.4-m-diameter cylindrical tank is completely filled with oil (SG 0.9)and rotates about its vertical longitudinal axis
egoroff_w [7]

Answer: p_{B} - p_{A} = 28800 Pa or 28.8 kPa

Explanation: To determine the pressure of a liquid in a rotating tank,it is used:

p = \frac{p_{fluid}.w^{2}.r^{2} }{2} - γfluid . z + c

where:

p_{fluid} is the liquid's density

w is the angular velocity

r is the radius

γfluid.z is the pressure variation due to centrifugal force.

For this question, the difference between a point on the circumference and a point on the axis will be:

p_{B} - p_{A} = \frac{p_{fluid}.w^{2}.r_{B} ^{2} }{2} - γfluid.z_{B} - (\frac{p_{fluid}.w^{2}.r_{A} ^{2} }{2} - γfluid.z_{A})

p_{B} - p_{A} = \frac{p_{fluid}.w^{2}}{2} (r_B^{2} - r_A^{2} ) - γfluid(z_{B} -z_{A})

Since there is no variation in the z-axis, z = 0 and that the density of oil is 0.9.10³kg/m³:

p_{B} - p_{A} = \frac{p_{fluid}.w^{2}}{2} (r_B^{2} - r_A^{2} )

p_{B} - p_{A} = \frac{0.9.10^3.40^2}{2}(0.2^2 - 0)

p_{B} - p_{A} = 28800

The difference in pressure between two points, one on the circumference and the other on the axis is p_{B} - p_{A} = 28800 Pa or 28.8 kPa

8 0
3 years ago
How can you use the IPDE Process to help protect motorcyclists while driving?
gladu [14]
Answer: you can use the IPDE process to protect motorcyclists while driving by identifying when a motorcycle is present, predicting what it will do next, deciding how to react to the other drivers decision, and exacting that decision.

I hope this helped
3 0
3 years ago
A product whose total work content time = 50 min is assembled on a manual production line at a rate of 24 units per hour. From p
valentinak56 [21]

Answer:

a)Cycle time = 2.37 min

b)Numbers of workers =21

c)Stations on the line =24

Explanation:

Given that

Total work content time(TWC) = 50 min

Production rate Rp= 24 units/hr

manning level will be close =1.5

Line balancing efficiency =0.94

a)

Cycle time

T_c=\dfrac{60E}{R_P}

T_c=\dfrac{60\times 0.95}{24}

Cycle time = 2.37 min

b)

Numbers of workers ,W

W=\dfrac{TWC}{T_c}

W=\dfrac{50}{2.37}

W= 21

Numbers of workers =21

c)

Stations on the line(n)

Lets find service time Ts

Ts = Cycle time -  Time for repositioning

Ts = Tc- Tr

Ts= 2.37  - 9/ 60 min

Ts= 2.22 min

We  know that efficiency

\eta=\dfrac{TWC}{n.T_s}

0.94=\dfrac{50}{n\times 2.22}

n=23.94  ⇒n=24

n=24

Stations on the line =24

7 0
3 years ago
The rectangular frame is composed of four perimeter two-force members and two cables AC and BD which are incapable of supporting
Rama09 [41]

Answer:

Your question is lacking some information attached is the missing part and the solution

A) AB = AD = BD = 0, BC = LC

    AC = \frac{5L}{3}T, CD = \frac{4L}{3} C

B) AB = AD = BC = BD = 0

   AC = \frac{5L}{3} T, CD = \frac{4L}{3} C

Explanation:

A) Forces in all members due to the load L in position A

assuming that BD goes slack from an inspection of Joint B

AB = 0 and BC = LC from Joint D, AD = 0 and CD = 4L/3 C

B) steps to arrive to the answer is attached below

AB = AD = BC = BD = 0

AC = \frac{5L}{3} T,  CD = \frac{4L}{3}C

7 0
4 years ago
Discuss in three points The old stone age
klasskru [66]

Answer:

Explanation:

<em>Early Stone Age</em>, or Paleolithic, <em>middle</em> and <em>Late Stone Age</em>, or Neolithic

Copper Age or Bronze Age also are part of the stone age

7 0
3 years ago
Read 2 more answers
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