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saul85 [17]
2 years ago
14

Five Safety for vernier height guage​

Engineering
1 answer:
yan [13]2 years ago
7 0

Explanation:

Whenever the vernier height gauge is not used, it should be kept in their cases. In long height gauges, to avoid its heating by warmth from the hands, care should be taken. The springing of the measuring jaw should be always avoided.

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Steam enters an adiabatic turbine at 8 MPa and 500C with a mass flow rate of 3
Vinil7 [7]

Answer:

a)temperature=69.1C

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Explanation:

Hello!

To solve this problem follow the steps below, the complete procedure is in the attached image

1. draw a complete outline of the problem

2. to find the temperature at the turbine exit  use termodinamic tables to find the saturation temperature at 30kPa

note=Through laboratory tests, thermodynamic tables were developed, these allow to know all the thermodynamic properties of a substance (entropy, enthalpy, pressure, specific volume, internal energy etc ..)  

through prior knowledge of two other properties such as pressure and temperature.  

3. Using thermodynamic tables find the enthalpy and entropy at the turbine inlet, then find the ideal enthalpy using the entropy of state 1 and the outlet pressure = 30kPa

4. The efficiency of the turbine is defined as the ratio between the real power and the ideal power, with this we find the real enthalpy.

Note: Remember that for a turbine with a single input and output, the power is calculated as the product of the mass flow and the difference in enthalpies.

5. Find the real power of the turbine

3 0
3 years ago
Does the location of a millimeter change the voltage or current of the circuit?
Cerrena [4.2K]

Answer:

Yes, it does.

Explanation:

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Before taking off a plane travels at a speed of 1/4 km per second. The runaway is 5 km. How many seconds does it take the plane
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Answer:

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4 0
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2) The switch in the circuit below has been closed a long time. At t=0, it is opened.
saul85 [17]

Answer:

  il(t) = e^(-100t)

Explanation:

The current from the source when the switch is closed is the current through an equivalent load of 15 + 50║50 = 15+25 = 40 ohms. That is, it is 80/40 = 2 amperes. That current is split evenly between the two parallel 50-ohm resistors, so the initial inductor current is 2/2 = 1 ampere.

The time constant is L/R = 0.20/20 = 0.01 seconds. Then the decaying current is described by ...

  il(t) = e^(-t/.01)

  il(t) = e^(-100t) . . . amperes

8 0
3 years ago
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