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1 year ago

Five Safety for vernier height guage

Engineering

1 answer:

yan [13]1 year ago

7 0

Explanation:

Whenever the vernier height gauge is not used, it should be kept in their cases. In long height gauges, to avoid its heating by warmth from the hands, care should be taken. The springing of the measuring jaw should be always avoided.

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Travel Time Problem: Compute the time of concentration using the Velocity, Sheet Flow Method for Non-Mountainous Orange County a

Vaselesa [24]

Answer:

Total time taken = 0.769 hour

Explanation:

using the velocity method

for sheet flow ;

Tt = $\frac{0.007(nl)^{0.8} }{(Pl)^{5}s^{0.4} }$

Tt = travel time

n = manning CaH

Pl = 25years

L = how length ( ft )

s = slope

For Location ( 1 )

s = 0.045

L = 1000 ft

n = 0.06 ( from manning's coefficient table )

Tt1 = 0.128 hour

For Location ( 2 )

s = 2.5 %

L= 750

n = 0.13

Tt2 = 0.239 hour

For Location ( 3 )

s = 1.5%

L = 500 ft

n = 0.15

Tt3 = 0.237 hour

For Location (4)

s = 0.5 %

L = 250 ft

n = 0.011

Tt4 = 0.165 hour

hence the Total time taken = Tt1 + Tt2 + Tt3 + Tt4

= 0.128 + 0.239 + 0.237 + 0.165 = 0.769 hour

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2 years ago

it creates parts from thin plastic sheets as opposed to plastic pellets. is it 1. Pickling 2. Thermoforming 3. Extrusion

iVinArrow [24]

Answer:

thermoforming

Explanation:

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4 0

2 years ago

Read 2 more answers

Select three ways an engineer can create a view of a design.

Angelina_Jolie [31]

Sketching projection

Sketching will give the brief planning of the engineering work to be done so it's important

Isometric projection

Yes doing a work in 3D factor out the mistakes which can be optimised

Third angle projection:-

Viewing angles matter a lot
So it will help the engineer to make it perfect from all angles

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1 year ago

Toeboards are usually ___ inches high and used on landings and balconies.

Ksju [112]

Answer:4 inches

Explanation:

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2 years ago

The pressure in an automobile tire depends on the temperature of the air in the tire. When the air temperature is 25°C, the pres

kirza4 [7]

Answer:

ΔP=19.76 KPa

$\Delta m=10^{-3}\ gm$

Explanation:

Given that

$T_1= 25C, P_1= 210 \KPa \gauge$

atmospheric pressure = 100 kPa.

So absolute pressure = Atmospheric pressure + gauge pressure

$P_1=210+100\ KPa$ (absolute)

$P_1=310\ KPa$ (absolute)

Here volume of air is constant .We know that for constant volume pressure

$\dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}$

here

$T_2= 44C$

$T_1=273+25=298K$

$T_2=273+44=317K$

$\dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}$

$\dfrac{310}{298}=\dfrac{P_2}{317}$

$P_2=329.76\ KPa$ (absolute)

So rise in pressure

$\Delta P=P_1-P_2$

ΔP=329.76-310 KPa

ΔP=19.76 KPa

$m_1=\dfrac{P_1V}{RT_1}$

$m_1=\dfrac{310\times 0.025}{0.287\times 298}$

$m_1=0.090615\ kg$

$m_2=\dfrac{P_2V}{RT_2}$

$m_2=\dfrac{329.76\times 0.025}{0.287\times 317}$

$m_2=0.090614\ kg$

Δm=0.090615 - 0.090614 kg

$\Delta m=10^{-3}\ gm$

4 0

2 years ago

Five Safety for vernier height guage​

Five Safety for vernier height guage