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2 years ago

5<2y<12 where y is an integer. Write down all the possible values of y.

Mathematics

1 answer:

frozen [14]2 years ago

8 0

Answer:

y = 3, 4, or 5

Step-by-step explanation:

Step 1; Simplify the Double Inequality

Let's first simplify this double inequality to make answering this problem a bit easier. This means getting the middle term to be just y, without any added constant or coefficients.

In this case, this is a fairly simple process, as all we have to do to get y by itself is just divide the entire inequality by 2. This means that we will also divide the 5 and 12 by 2. (Note that the signs stay the same because we are not dividing by a negative number.)

Doing so gives us the following double inequality: 2.5 < y < 6.

Step 2: Identify the Integers in this Range

Now that we have a simplified double inequality, all we need to do is find all of the integers in its range. (Recall that an integer is any number that is not a fraction when fully simplified (ex. …-1, 0, 1...).)

In other words, we need to find all of the integers in between 2.5 and 6. Note that we don't include 6 because of the "<" sign, which indicates that the 2.5 and 6 are not included in the set. These numbers are 3, 4, and 5, making them your answer. Hope this helps!

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3 years ago

Find a ratio equivalent to 12/21 with lower terms

dmitriy555 [2]

Find factors of 12 and 21

Divide 3 from both numerator and denominator.

(12/21)/(3/3) = 4/7

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hope this helps

3 0

3 years ago

Read 2 more answers

A scuba diving company currently charges $100per dive. On average, there are 30 customers per day. The company performed a study

Semenov [28]

A. Total Revenue (R) is equal to price per dive (P) multiplied by number of customers (C). We can write $R=PC$ .

Per price increase is $20. So four price increase is $ $20*4=$80$ . Hence, price per dive is 100+80=$180.

Also per price increase, 2 customers are reduced from 30. For 4 price increases, $4*2=8$ customers are reduced. Hence, total customers is $30-8=22$ .

So Total Revenue is:

$R=180*22=3960$

B. Each price increase is 20. So x price increase is 20x. Hence, new price per dive would be equal to the sum of 100 and 20x.

Also per price increase, customers decrease by 2. So per x price increases, the customer decrease is 2x. Hence, new number of customers is the difference of 30 and 2x.

Therefor we can write the quadratic equation for total revenue as the new price times the new number of customers.

$R=(100+2x)(30-2x)=-40x^{2}+400x+3000$

C. We are looking for the point (x) at which the equation modeled in part (B) gives a maximum value of revenue (y). That x value is given as $x=-\frac{b}{2a}$ , where a is the coefficient of $x^{2}$ and b is the coefficient of x. So we have,

$x=-\frac{b}{2a}=- \frac{400}{(2)(-40)}=5$

That means, the greatest revenue is achieved after 5 price increases. Each price increase was 20, so 5 price increase would be $5*20=100$ . So the price that gives the greatest revenue is $100+100=200$ .