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dmitriy555 [2]
2 years ago
14

Consider the carnival ride in which the rider stands against the wall inside a large cylinder. The ride then starts to spin whic

h accelerates the rider to speed v such that the centripetal force supplied by the normal force of the cylinder wall on the rider's back supplies enough friction to support the rider's weight. Assume the rider has a mass of 65 kg and the radius of the spinning cylinder is 6.0 m. What speed does the rider have to be spinning when the floor drops out beneath her, if the normal force must be at least half their weight? Answer in m/s.
Physics
1 answer:
ArbitrLikvidat [17]2 years ago
6 0

The speed at which the rider is spinning when the floor drops out beneath her is 5.42 m/s.

<h3>Acceleration of the rider </h3>

The acceleration of the rider when the normal force is half their weight is calculated as follows;

Fn = 0.5(W)

ma = 0.5 x mg

65 x a  = 0.5 x 65 x 9.8

a =  0.5 x 9.8

a = 4.9 m/s²

<h3>Speed of the rider</h3>

a = v²/r

v² = ar

v = √ar

v = √(4.9 x 6)

v = 5.42 m/s

Learn more about speed here: brainly.com/question/6504879

#SPJ1

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An unknown mass of each substance, initially at 25.0 ∘C, absorbs 1920 J of heat. The final temperature is recorded. Find the mas
zhannawk [14.2K]

Answer: mass for Pyrex glass 84.21g

mass for sand 61.6g

mass for ethanol 41.32g

mass for water 62.07g

Explanation

By definition specific heat is the amount of heat required to change the temperature of 1 kg mas by 1°C

Q=mcΔT is formula for specific heat

Q is heat transfer

m is mass

ΔT is change in temperature

c   is specific heat

c of Pyrex glass= 0.75 j/g°C

c of sand = 0.84 j/g°C

c of ethanol= 2.42 j/g°C

c of water = 4.18 j/g°C

now we will make M(mass) the subject, so equation becomes

m=Q/cΔT

for

pyrex glass T<em>f=</em>55.4°C

m=1920/(55.4-25)*0.75

m=84.21g {after cutting J(joules) and °C we are left with g(grams)}

for

sand T<em>f</em>=62.1°C

m=1920/(62.1-25)*0.84

m=61.6g {after cutting J(joules) and °C we are left with g(grams)}

for

ethanol T<em>f</em>=44.2°C

m=1920/(44.2-25)*2.42

m=41.32g  {after cutting J(joules) and °C we are left with g(grams)}

for

water T<em>f=</em>32.4°

m=1920/(32.4-25)*4.18

m=62.07g  {after cutting J(joules) and °C we are left with g(grams)}

i hope you understand the solution, thank you.

7 0
3 years ago
. Set the applied force to Force necessary to Keep the box Moving without accelerating. Restart the animation. Just before the b
Arte-miy333 [17]

Answer:

elative magnitude of the two forces is the same and they are applied in a constant direction.

Explanation:

Newton's second law states that the sum of the forces is equal to the mass times the acceleration  

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in this case there are two forces on the x axis

             F_applied - fr = 0

since they indicate that the velocity is constant, consequently

             F_applied = fr

the relative magnitude of the two forces is the same and they are applied in a constant direction.

3 0
3 years ago
In the game of 9-ball, the pool balls are initially placed in a grouping of which shape?
elixir [45]
It should be a triangle.
8 0
4 years ago
Georgie was pulling her brother (of mass 16 kg) in a 9.4 kg sled with a constant force of 39 N for one block (128 m). How much w
Genrish500 [490]

Answer:

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Explanation:

Force, F = 39 N

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Thus, the work done is 4992 J.

7 0
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a block of wood loses 160 j of gravitational potential energy as it slides down a ramp. if it has 90 J of kinetic energy at the
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It would go slower there needs to be more gravity to go faster
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