Answer:
The amplitude of the wave is 0.02 m.
Explanation:
Given that,
Maximum speed = 2.0 m/s
Maximum acceleration = 200 m/s²
We need to calculate the angular frequency
Using formula of angular frequency
Put the value into the formula
We need to calculate the amplitude of the wave
Using formula of velocity
Put the value into the formula
Hence, The amplitude of the wave is 0.02 m.
Answer:
(a) work required to lift the object is 1029 J
(b) the gravitational potential energy gained by this object is 1029 J
Explanation:
Given;
mass of the object, m = 35 kg
height through which the object was lifted, h = 3 m
(a) work required to lift the object
W = F x d
W = (mg) x h
W = 35 x 9.8 x 3
W = 1029 J
(b) the gravitational potential energy gained by this object is calculated as;
ΔP.E = Pf - Pi
where;
Pi is the initial gravitational potential energy, at initial height (hi = 0)
ΔP.E = (35 x 9.8 x 3) - (35 x 9.8 x 0)
ΔP.E = 1029 J
Both electric force and gravitational force are conservative and obey inverse square law.
The electric force between two charges q and q' separated by a distance r is calculated as-
Here K is the proportionality constant whose value is
The gravitational force between two masses m and m' separated by a distance r is given as -
Here K' is the proportionality constant whose value is G .
G is called gravitational force constant and its value is given
The electric force is a stronger force and gravitational force is a weaker force.
It is obvious that the value of constant for electric force is much larger than the gravitational force constant.
Out of the four options given in the question the the option four is the correct answer i.e D) The electrical force is much larger than the gravitational force because 10^9 is much greater than 10–11.
Answer:
90.3125 m
Explanation:
a = 10m/s^2 (constant)
S=height
U=initial velocity
a= gravitational acceleration
t= time
s = 0 + 1/2 * 10 * 4.25 ^2
u is 0 because it is dropped without velocity
s =90.3125 m